grating has a total width of 5 cm and 500 slits per mm. When the grating is illuminated by a ane wave with wavelength of λ = 633nm, the fourth order (m = 4) of the grating diffraction aximum (peak) is located in the first minimum of the single slit diffraction. Compute the width of each transparent slit of the grating (b). Based on Rayleigh criterion, find out the maximum resolvable wave length difference (A2) m 2 grating diffraction order around this wavelength (λ = 633nm).

icon
Related questions
Question
A grating has a total width of 5 cm and 500 slits per mm. When the grating is illuminated by a
plane wave with wavelength of λ = 633nm, the fourth order (m = 4) of the grating diffraction
maximum (peak) is located in the first minimum of the single slit diffraction.
1) Compute the width of each transparent slit of the grating (b).
2) Based on Rayleigh criterion, find out the maximum resolvable wave length difference (Aλ) at
m = 2 grating diffraction order around this wavelength (2 = 633nm).
Transcribed Image Text:A grating has a total width of 5 cm and 500 slits per mm. When the grating is illuminated by a plane wave with wavelength of λ = 633nm, the fourth order (m = 4) of the grating diffraction maximum (peak) is located in the first minimum of the single slit diffraction. 1) Compute the width of each transparent slit of the grating (b). 2) Based on Rayleigh criterion, find out the maximum resolvable wave length difference (Aλ) at m = 2 grating diffraction order around this wavelength (2 = 633nm).
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer