Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![**Graph the Circle**
The equation of the circle is given by:
\[
(x + 1)^2 + (y + 4)^2 = 16
\]
To graph the circle, use the graphing tool located on the right. Click to enlarge the graph for a better view of its details.
*Graph Description*: The image includes a small button labeled "Click to enlarge graph," featuring an icon of a graph with a circular plot, indicating interactivity for users to better view and manipulate the graph for educational purposes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd93b8e4e-eb18-4d67-999e-d4b618f7a1a7%2F8e58f918-0f84-4e9a-b2e5-e38a1cc37890%2F9y1618_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Graph the Circle**
The equation of the circle is given by:
\[
(x + 1)^2 + (y + 4)^2 = 16
\]
To graph the circle, use the graphing tool located on the right. Click to enlarge the graph for a better view of its details.
*Graph Description*: The image includes a small button labeled "Click to enlarge graph," featuring an icon of a graph with a circular plot, indicating interactivity for users to better view and manipulate the graph for educational purposes.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
the given equation is:
the above equation can be written as:
as we know the equation of the circle having centre at (h,k ) and radius r is:
therefore compare the equation with the equation .
therefore, h=-1, k=-4 and r=4.
therefore is the equation of the circle having centre at (-1,-4) and radius equal to 4.
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