Graph the circle. x+12+42 = 16 42=D Use the graphing tool on the right to graph the circle. Click to enlarge graph

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Graph the Circle**

The equation of the circle is given by:

\[
(x + 1)^2 + (y + 4)^2 = 16
\]

To graph the circle, use the graphing tool located on the right. Click to enlarge the graph for a better view of its details.

*Graph Description*: The image includes a small button labeled "Click to enlarge graph," featuring an icon of a graph with a circular plot, indicating interactivity for users to better view and manipulate the graph for educational purposes.
Transcribed Image Text:**Graph the Circle** The equation of the circle is given by: \[ (x + 1)^2 + (y + 4)^2 = 16 \] To graph the circle, use the graphing tool located on the right. Click to enlarge the graph for a better view of its details. *Graph Description*: The image includes a small button labeled "Click to enlarge graph," featuring an icon of a graph with a circular plot, indicating interactivity for users to better view and manipulate the graph for educational purposes.
Expert Solution
Step 1

the given equation is:

x+12+y+42=16

the above equation can be written as:

x+12+y+42=16x--12+y--42=42

as we know the equation of the circle having centre at (h,k ) and radius r is:

x-h2+y-k2=r2

therefore compare the equation x--12+y--42=42 with the equation x-h2+y-k2=r2.

therefore, h=-1, k=-4 and r=4.

therefore x+12+y+42=16 is the equation of the circle having centre at (-1,-4) and radius equal to 4.

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