Write an equation that represents each circle. 1. (-2, 4) 4 -7 6 4- 3 -6 -2 -4 2. in

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Write an equation that represents each circle.

**Title: Writing Equations of Circles**

In this exercise, we will learn how to write the equations that represent two given circles on a coordinate plane. 

**Problem 1:**

Observe the first circle graph:

1. **Description:**
   - The center of the circle is located at (-2, 4).
   - The circle passes through several points, but notably through the number 6 on the y-axis and -2 on the x-axis, showing that the radius extends from -2 to 4, up to -2 to 8. 
   - Radius: The radius can be identified as the distance from the center to the perimeter of the circle. Here, it has a length of 4 units.

   **Graph Details:**
   - The x-axis ranges from -7 to 2.
   - The y-axis ranges from 0 to 8.
   - The circle is centered at (-2, 4) and has a radius of 4.

**Equation:**

Using the standard equation for a circle \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius, we substitute the values:

- Center \((h, k) = (-2, 4)\)
- Radius \(r = 4\)

So, the equation for the first circle is:

\[
(x + 2)^2 + (y - 4)^2 = 16
\]

**Problem 2:**

Observe the second circle graph:

2. **Description:**
   - The center of the circle is located at (0, 0), which is the origin.
   - The circle passes through several points, extending 8 units in every direction from the center, confirming that the radius is 8 units.

   **Graph Details:**
   - The x-axis ranges from -8 to 8.
   - The y-axis ranges from -8 to 8.
   - The circle is centered at the origin (0, 0) and has a radius of 8.

**Equation:**

Using the standard equation for a circle \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius, we substitute the values:

- Center \((h,
Transcribed Image Text:**Title: Writing Equations of Circles** In this exercise, we will learn how to write the equations that represent two given circles on a coordinate plane. **Problem 1:** Observe the first circle graph: 1. **Description:** - The center of the circle is located at (-2, 4). - The circle passes through several points, but notably through the number 6 on the y-axis and -2 on the x-axis, showing that the radius extends from -2 to 4, up to -2 to 8. - Radius: The radius can be identified as the distance from the center to the perimeter of the circle. Here, it has a length of 4 units. **Graph Details:** - The x-axis ranges from -7 to 2. - The y-axis ranges from 0 to 8. - The circle is centered at (-2, 4) and has a radius of 4. **Equation:** Using the standard equation for a circle \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius, we substitute the values: - Center \((h, k) = (-2, 4)\) - Radius \(r = 4\) So, the equation for the first circle is: \[ (x + 2)^2 + (y - 4)^2 = 16 \] **Problem 2:** Observe the second circle graph: 2. **Description:** - The center of the circle is located at (0, 0), which is the origin. - The circle passes through several points, extending 8 units in every direction from the center, confirming that the radius is 8 units. **Graph Details:** - The x-axis ranges from -8 to 8. - The y-axis ranges from -8 to 8. - The circle is centered at the origin (0, 0) and has a radius of 8. **Equation:** Using the standard equation for a circle \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius, we substitute the values: - Center \((h,
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