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Graph A AN f(-2) =-2 lim_ f(z) =3 lim_ f(z) = [1] lim f(z) DNE Graph C f(-2)=0 _lim_f(z) = lim_ f(z) = z+-2+ lim, f(x) = Graph B f(-2) = 0 lim_f(z) = #-+-2 _lim_f(z) = lim f(z)= Graph D f(-2) = lim_f(z) = lim_f(z) = 2+2+ lim, f(z) =

Graph A AN f(-2) =-2 lim_ f(z) =3 lim_ f(z) = [1] lim f(z) DNE Graph C f(-2)=0 _lim_f(z) = lim_ f(z) = z+-2+ lim, f(x) = Graph B f(-2) = 0 lim_f(z) = #-+-2 _lim_f(z) = lim f(z)= Graph D f(-2) = lim_f(z) = lim_f(z) = 2+2+ lim, f(z) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Graph A AA f(-2) = -2 lim f(x)=3 lim f(x) = 1 24-2+ lim f(z) = DNE Graph C f(-2) = lim_f(x): -2- = lim_ f(x) = + 2+ lim, f(x) = Graph B f(-2) = lim_ f(x) = x+2 lim f(x)= 2+2+ lim f(x) = 0 Graph D f(-2): lim_ f(x) = lim_ f(x) = *+-2+ lim, f(x) =
Transcribed Image Text:Graph A AA f(-2) = -2 lim f(x)=3 lim f(x) = 1 24-2+ lim f(z) = DNE Graph C f(-2) = lim_f(x): -2- = lim_ f(x) = + 2+ lim, f(x) = Graph B f(-2) = lim_ f(x) = x+2 lim f(x)= 2+2+ lim f(x) = 0 Graph D f(-2): lim_ f(x) = lim_ f(x) = *+-2+ lim, f(x) =
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