gramming Language: Java Direction: Write a program to determine the number of PASSED and FAILED out of 15 inputted names with the corresponding grade. Restrict the inputted grade for each name in the range of 50 to 100, in which 75 is the passing grade. If the inputted gr

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Programming Language: Java

Direction: Write a program to determine the number of PASSED and FAILED out of 15 inputted names with the corresponding grade. Restrict the inputted grade for each name in the range of 50 to 100, in which 75 is the passing grade. If the inputted grade is not on the range, the program will remind the user of a message for the accepted range for the grade and allows the user to re-enter a grade.

 

NOTE: MUST ADD COMMENTS

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please help me fix the error im using java eclipse as my IDE

Main.java X
1 public class Main {
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public static void main(String[] args) {
//initialize the variables
}
int pass = 0;
int fail = 0;
int numOfNames = 15;
//create a for loop to prompt the user 15 times
for (int i = 0; i < numOfNames; i++) {
//prompt the user to enter a name
System.out.print("Please enter the name: ");
String name = System.console().readLine();
//prompt the user to enter the grade
System.out.print("Please enter the grade: ");
int grade = Integer.parseInt(System.console().readLine());
//check if the grade is in the accepted range
while (grade < 50 || grade > 100) {
//if the grade is not in range, prompt the user to enter a valid grade
System.out.print("Please enter a valid grade between 50 and 100: ");
grade = Integer.parseInt(System.console().readLine());
}
//if the grade is 75 or greater, increment the pass counter
if (grade >= 75) {
pass++;
}
//otherwise increment the fail counter
else {
fail++;
}
}
//print the results
System.out.println("Number
System.out.println("Number
of PASSED:
+ pass);
of FAILED: " + fail);
Transcribed Image Text:Main.java X 1 public class Main { 20 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 } public static void main(String[] args) { //initialize the variables } int pass = 0; int fail = 0; int numOfNames = 15; //create a for loop to prompt the user 15 times for (int i = 0; i < numOfNames; i++) { //prompt the user to enter a name System.out.print("Please enter the name: "); String name = System.console().readLine(); //prompt the user to enter the grade System.out.print("Please enter the grade: "); int grade = Integer.parseInt(System.console().readLine()); //check if the grade is in the accepted range while (grade < 50 || grade > 100) { //if the grade is not in range, prompt the user to enter a valid grade System.out.print("Please enter a valid grade between 50 and 100: "); grade = Integer.parseInt(System.console().readLine()); } //if the grade is 75 or greater, increment the pass counter if (grade >= 75) { pass++; } //otherwise increment the fail counter else { fail++; } } //print the results System.out.println("Number System.out.println("Number of PASSED: + pass); of FAILED: " + fail);
Please enter the name: Exception in thread "main"
at Main.main (Main.java:11
java.lang.NullPointerException:
Cannot invoke "java.io.Console.read
Transcribed Image Text:Please enter the name: Exception in thread "main" at Main.main (Main.java:11 java.lang.NullPointerException: Cannot invoke "java.io.Console.read
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