Good Programming practices help in improving programs readability and understandability both for a programmer and for a general user. What changes would you make in the following program, written by a beginner, keeping in view the good programming practices. You are also required to write the output of the program if a user wants to find factorial of number 6. Note: The Program finds/calculates factorial of a number using a user defined recursive function. #include using namespace std; int f(int n); int main() { int n; cout << "Enter: "; cin >> n; cout << "Answer = " < 1) return n * f(n - 1); else return 1; }
Good Programming practices help in improving programs readability and understandability both for a programmer and for a general user. What changes would you make in the following program, written by a beginner, keeping in view the good programming practices. You are also required to write the output of the program if a user wants to find factorial of number 6. Note: The Program finds/calculates factorial of a number using a user defined recursive function. #include using namespace std; int f(int n); int main() { int n; cout << "Enter: "; cin >> n; cout << "Answer = " < 1) return n * f(n - 1); else return 1; }
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Good
and understandability both for a programmer and for a general user.
What changes would you make in the following program, written by a
beginner, keeping in view the good programming practices.
You are also required to write the output of the program if a user wants
to find factorial of number 6.
Note: The Program finds/calculates factorial of a number using a user
defined recursive function.
#include<iostream>
using namespace std;
int f(int n);
int main()
{
int n;
cout << "Enter: ";
cin >> n;
cout << "Answer = " <<factorial(n);
return 0;
}
int f(int n)
{
if(n > 1)
return n * f(n - 1);
else
return 1;
}
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