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goes through a change from state 1 (27 °C, 1 bar, 1.4 cm ³/g) to state 2 (T °C, P ban and V cm³/g). Given the values for T, P and V in Table 1 and also given that the isothermal compressibility is 47 x 106 /bar, determine methanol's volume expansivity. Provide any necessary derivation(s) and assumptions in your solution. Table 1

goes through a change from state 1 (27 °C, 1 bar, 1.4 cm ³/g) to state 2 (T °C, P ban and V cm³/g). Given the values for T, P and V in Table 1 and also given that the isothermal compressibility is 47 x 106 /bar, determine methanol's volume expansivity. Provide any necessary derivation(s) and assumptions in your solution. Table 1

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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The value for T is 32, for P is 0.6, for V is 1.48

Liquid methanol goes through a change from state 1 (27 °C, 1 bar, 1.4 cm /g) to state 2 (T °C, P bar and V cm/g). Given the values for T, P and V in Table 1 and also given that the isothermal compressibility is 47 x 10 /bar, determine methanol's volume expansivity. Provide any necessary derivation(s) and assumptions in your solution. Table 1
Transcribed Image Text:Liquid methanol goes through a change from state 1 (27 °C, 1 bar, 1.4 cm /g) to state 2 (T °C, P bar and V cm/g). Given the values for T, P and V in Table 1 and also given that the isothermal compressibility is 47 x 10 /bar, determine methanol's volume expansivity. Provide any necessary derivation(s) and assumptions in your solution. Table 1
Expert Solution
Step 1

Given

STATE 1

P1= 1barT1= 270C = 300 KV1= 1.4 cm3g

STATE 2

T2 = 320C=305.15 KV2= 1.48 cm3gP2= 0.6 bar

Isothermal compressibility , K = 47×10- 6 bar

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