Glucose-1-phosphate is converted to Glucose-6 phosphate by an enzyme. The equilibrium constant in biochemical standard conditions is 19. Answer the following four questions regarding this enzyme-catalyzed reaction. Glucose−1−PO24−⟶Glucose−6−PO24− KRxn′=19 R=8.314Jmol•K ∆G°′=−RTlnK′ ∆G′=∆G°′+RTlnQ′ Part 1: If the concentration of Glucose-1-phosphate is 10.36 µM at equilibrium, what is the concentration of Glucose-6-phosphate in µM? Round to the ones place. Thank you! Part 2: If the reaction is not at equilibrium, what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 37.61µM and the concentration of Glucose-6-phosphate is 1.56 mM? Answer in Joules. Pay attention to units. Round to the correct number of significant figures. (There are 103 µM in 1mM.) Thank You! I got the first two parts of this question, I am having a difficult time with A and B)
Glucose-1-phosphate is converted to Glucose-6 phosphate by an enzyme. The equilibrium constant in biochemical standard conditions is 19. Answer the following four questions regarding this enzyme-catalyzed reaction. Glucose−1−PO24−⟶Glucose−6−PO24− KRxn′=19 R=8.314Jmol•K ∆G°′=−RTlnK′ ∆G′=∆G°′+RTlnQ′ Part 1: If the concentration of Glucose-1-phosphate is 10.36 µM at equilibrium, what is the concentration of Glucose-6-phosphate in µM? Round to the ones place. Thank you! Part 2: If the reaction is not at equilibrium, what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 37.61µM and the concentration of Glucose-6-phosphate is 1.56 mM? Answer in Joules. Pay attention to units. Round to the correct number of significant figures. (There are 103 µM in 1mM.) Thank You! I got the first two parts of this question, I am having a difficult time with A and B)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Glucose-1-phosphate is converted to Glucose-6 phosphate by an enzyme. The equilibrium constant in biochemical standard conditions is 19.
Answer the following four questions regarding this enzyme-catalyzed reaction.
Glucose−1−PO24−⟶Glucose−6−PO24−
KRxn′=19
R=8.314Jmol•K
∆G°′=−RTlnK′
∆G′=∆G°′+RTlnQ′
Part 1:
If the concentration of Glucose-1-phosphate is 10.36 µM at equilibrium, what is the concentration of Glucose-6-phosphate in µM? Round to the ones place.
Thank you!
Part 2:
If the reaction is not at equilibrium, what is ∆G' at 25°C if the concentration of Glucose-1-phosphate is 37.61µM and the concentration of Glucose-6-phosphate is 1.56 mM?
Answer in Joules. Pay attention to units.
Round to the correct number of significant figures.
(There are 103 µM in 1mM.)
Thank You!
I got the first two parts of this question, I am having a difficult time with A and B)
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