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Given: • VDD = 21 V • R, =16 kohms • R2 = 5 kohms • Rp = 664 ohms • Rg = 0 kohms • R = 10 kohms • IDron) = 16 mA at VGs(on) = 5 V • VGsith) = 2 V Em = 27 ms Solve: Answers should be expressed using 2 decimal places 1. k (transfer constant) = Blank 1 mA/V2 2. I, = Blank 2 mA %3D 3. VG = Blank 3 V %3D

Given: • VDD = 21 V • R, =16 kohms • R2 = 5 kohms • Rp = 664 ohms • Rg = 0 kohms • R = 10 kohms • IDron) = 16 mA at VGs(on) = 5 V • VGsith) = 2 V Em = 27 ms Solve: Answers should be expressed using 2 decimal places 1. k (transfer constant) = Blank 1 mA/V2 2. I, = Blank 2 mA %3D 3. VG = Blank 3 V %3D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Given: • VDD = 21 V • R, =16 kohms R2 = 5 kohms • Rp = 664 ohms • Rg = 0 kohms • R_ = 10 kohms Ipron) = 16 mA at Vesion) = 5 V • Vas(th) = 2 V • Em = 27 ms Solve: Answers should be expressed using 2 decimal places 1. k (transfer constant) = Blank 1 mA/V 2. Ip = Blank 2 mA 3. VG = Blank 3 V 4. Vs = Blank 4 V 5. VGs = Blank 5 V 6. Vps = Blank 6 V 7. Rinſtot) = Blank 7 kohms 8. Voltage gain, A, = Blank 8 %3D %3D
Transcribed Image Text:Given: • VDD = 21 V • R, =16 kohms R2 = 5 kohms • Rp = 664 ohms • Rg = 0 kohms • R_ = 10 kohms Ipron) = 16 mA at Vesion) = 5 V • Vas(th) = 2 V • Em = 27 ms Solve: Answers should be expressed using 2 decimal places 1. k (transfer constant) = Blank 1 mA/V 2. Ip = Blank 2 mA 3. VG = Blank 3 V 4. Vs = Blank 4 V 5. VGs = Blank 5 V 6. Vps = Blank 6 V 7. Rinſtot) = Blank 7 kohms 8. Voltage gain, A, = Blank 8 %3D %3D
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