Four Pulley SystemS = 40cmS, = 9cmSince the weight of load is in grams, we convert grams to dynes. Then0.001kg100000F, = 200g x-1 gm= 0.2kg × 9.8–= 1.96N x-= 196000 dynes1 NF; = 50g x 0.001kg1g100000= 0.05kg × 9.8= 0.49N × -49000 dynes1NFormula:IMA =SoАМАWhere,AMA is the Actual Mechanical AdvantageIMA is the Ideal or Theoretical Mechanical AdvantageF, is the output forceF; is the input forceSį is input distanceS, is output distanceSolution:Two Pulley System:To get the actual mechanical advantage (AMA):196000 dynesAMA = '2.105263 = 2.1193100 dynesTo get the ideal mechanical advantage (IMA):IMA = L =58cm= 1.933 × 1.93SoзостFour Pulley System:To get the actual mechanical advantage (AMA):Fo 196000 dynes49000 dynesАМАFiTo get the ideal mechanical advantage (IMA):IMA = SL;40cm – 4.44 z 4.44So9cm Given:Two Pulley SystemS = 58cmS, = 30cm%3DSince the weight of load is in grams, we convert grams to dynes. Then0.001kg100000F, = 200g ×= 0.2kg × 9.8–= 1.96N ×-1 g= 196000 dynes1N0.001kg100000F; = 95g ×= 0.095kg × 9.8 = 0.931N ×1g= 93100 dyness21 N

Given: Two pulley system Si=58 cmS0=30 cm F0=196000 dynesFi=93100 dynes To find: AMA and IMA

Answered: Given: Two Pulley System S = 58cm S, =…

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Given: Two Pulley System S = 58cm S, = 30cm Since the weight of load is in grams, we convert grams to dynes. Then 0.001kg 100000 = 0.2kg × 9.8" = 1.96N × 1 g = 196000 dynes 1 N 100000 F, = 200g × %3D %3D s2 F; = 95g × 0.001kg = 0.095kg × 9.8–= 0.931N × m %3D = 93100 dynes %3D 1 N