Given: Two Pulley System S = 58cm S, = 30cm Since the weight of load is in grams, we convert grams to dynes. Then 0.001kg 100000 = 0.2kg × 9.8" = 1.96N × 1 g = 196000 dynes 1 N 100000 F, = 200g × %3D %3D s2 F; = 95g × 0.001kg = 0.095kg × 9.8–= 0.931N × m %3D = 93100 dynes %3D 1 N
Given: Two Pulley System S = 58cm S, = 30cm Since the weight of load is in grams, we convert grams to dynes. Then 0.001kg 100000 = 0.2kg × 9.8" = 1.96N × 1 g = 196000 dynes 1 N 100000 F, = 200g × %3D %3D s2 F; = 95g × 0.001kg = 0.095kg × 9.8–= 0.931N × m %3D = 93100 dynes %3D 1 N
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Transcribed Image Text:Four Pulley System
S = 40cm
S, = 9cm
Since the weight of load is in grams, we convert grams to dynes. Then
0.001kg
100000
F, = 200g x-
1 g
m
= 0.2kg × 9.8–= 1.96N x-
= 196000 dynes
1 N
F; = 50g x 0.001kg
1g
100000
= 0.05kg × 9.8= 0.49N × -
49000 dynes
1N
Formula:
IMA =
So
АМА
Where,
AMA is the Actual Mechanical Advantage
IMA is the Ideal or Theoretical Mechanical Advantage
F, is the output force
F; is the input force
Sį is input distance
S, is output distance
Solution:
Two Pulley System:
To get the actual mechanical advantage (AMA):
196000 dynes
AMA = '
2.105263 = 2.11
93100 dynes
To get the ideal mechanical advantage (IMA):
IMA = L =
58cm
= 1.933 × 1.93
So
зост
Four Pulley System:
To get the actual mechanical advantage (AMA):
Fo 196000 dynes
49000 dynes
АМА
Fi
To get the ideal mechanical advantage (IMA):
IMA = SL;
40cm – 4.44 z 4.44
So
9cm
Transcribed Image Text:Given:
Two Pulley System
S = 58cm
S, = 30cm
%3D
Since the weight of load is in grams, we convert grams to dynes. Then
0.001kg
100000
F, = 200g ×
= 0.2kg × 9.8–= 1.96N ×-
1 g
= 196000 dynes
1N
0.001kg
100000
F; = 95g ×
= 0.095kg × 9.8 = 0.931N ×
1g
= 93100 dynes
s2
1 N
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