Given the two reactions 3. PbCl₂(aq) = Pb²+ (aq) + 2Cl(aq), K3=1.79x10-10, and 4. AgCl(aq) Ag+ (aq) + Cl(aq), K-1.15x104. what is the equilibrium constant Kfinal for the following reaction? Express your answer numerically. View Available Hint(s) for Part B for Part @do for Part redo foart B resor Part B keyboard shortcuts for Part B help for Part B Kfinal 1.32 10-² Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining PbCl₂(aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq)
Given the two reactions 3. PbCl₂(aq) = Pb²+ (aq) + 2Cl(aq), K3=1.79x10-10, and 4. AgCl(aq) Ag+ (aq) + Cl(aq), K-1.15x104. what is the equilibrium constant Kfinal for the following reaction? Express your answer numerically. View Available Hint(s) for Part B for Part @do for Part redo foart B resor Part B keyboard shortcuts for Part B help for Part B Kfinal 1.32 10-² Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining PbCl₂(aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Part B
Given the two reactions
3. PbCl₂ (aq) = Pb²+ (aq) + 2Cl(aq), K3=1.79x10-10, and
4. AgCl(aq) Ag+ (aq) + Cl(aq), K₁=1.15x10-4,
what is the equilibrium constant Kfinal for the following reaction?
Express your answer numerically.
► View Available Hint(s)
for Part B for Part&do for Part redo fol Part B resor Part B keyboard shortcuts for Part B help for Part B
-2
Kfinal = 1.32
10-²
Submit
●
Previous Answers
X Incorrect; Try Again; 5 attempts remaining
PbCl₂ (aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6bef7ac-cf61-4524-8407-996ead7a26b1%2F6a4f5bcd-d47b-4668-b182-b308107465d4%2F1vfbphg_processed.png&w=3840&q=75)
Transcribed Image Text:Part B
Given the two reactions
3. PbCl₂ (aq) = Pb²+ (aq) + 2Cl(aq), K3=1.79x10-10, and
4. AgCl(aq) Ag+ (aq) + Cl(aq), K₁=1.15x10-4,
what is the equilibrium constant Kfinal for the following reaction?
Express your answer numerically.
► View Available Hint(s)
for Part B for Part&do for Part redo fol Part B resor Part B keyboard shortcuts for Part B help for Part B
-2
Kfinal = 1.32
10-²
Submit
●
Previous Answers
X Incorrect; Try Again; 5 attempts remaining
PbCl₂ (aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq)
![Part A
For the reaction
Kc = 82.8 at a temperature of 169 °C.
Calculate the value of Kp.
Express your answer numerically.
► View Available Hint(s)
-7
Kp 5.07 10¯
Submit Previous Answers
Part B
for Part A for Part A do for Part redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A
X Incorrect; Try Again; 5 attempts remaining
For the reaction
Kp
●
= 1.06x10-² at a temperature of 151 °C.
Kc =
Calculate the value of Ke.
Express your answer numerically.
► View Available Hint(s)
Submit
for Part B for Part B do for Part redo for Part B resetor Part B keyboard shortcuts for Part B help for Part B
3A(g) + 3B (g) = C(g)
X(g) + 2Y(g) = 3Z(g)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6bef7ac-cf61-4524-8407-996ead7a26b1%2F6a4f5bcd-d47b-4668-b182-b308107465d4%2Fkm8ld6_processed.png&w=3840&q=75)
Transcribed Image Text:Part A
For the reaction
Kc = 82.8 at a temperature of 169 °C.
Calculate the value of Kp.
Express your answer numerically.
► View Available Hint(s)
-7
Kp 5.07 10¯
Submit Previous Answers
Part B
for Part A for Part A do for Part redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A
X Incorrect; Try Again; 5 attempts remaining
For the reaction
Kp
●
= 1.06x10-² at a temperature of 151 °C.
Kc =
Calculate the value of Ke.
Express your answer numerically.
► View Available Hint(s)
Submit
for Part B for Part B do for Part redo for Part B resetor Part B keyboard shortcuts for Part B help for Part B
3A(g) + 3B (g) = C(g)
X(g) + 2Y(g) = 3Z(g)
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