Given the thermochemical equations X, + 3 Y, → 2XY, ΔΗ = -390 kJ - X, + 2Z, – 2 XZ, AH2 = -120 kJ %3D 2 Y, + Z, → 2 Y,Z AH3 = -240 kJ Calculate the change in enthalpy for the reaction. 4XY, + 7Z, - 6 Y,Z + 4 XZ, ΔΗ=

Given the thermochemical equations X, + 3 Y, → 2XY, ΔΗ = -390 kJ - X, + 2Z, – 2 XZ, AH2 = -120 kJ %3D 2 Y, + Z, → 2 Y,Z AH3 = -240 kJ Calculate the change in enthalpy for the reaction. 4XY, + 7Z, - 6 Y,Z + 4 XZ, ΔΗ=

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: 1. Calculate A H for 2S (s) + 302 (g) → 6FE203 based on the reactions: 2H2S (g) + 302 (g)→2SO2(g) +…

Q: 2-Given the thermochemical equations X2+3Y2⟶2XY3Δ?1=−340 kJ X2+3Y2⟶2XY3ΔH1=−340 kJ…

A: X2 + 3Y2 ⟶ 2XY3 ΔH1 = −340 kJ ......................(1) X2 + 2Z2 ⟶…

Q: heat

Q: 1. Determine the change in enthalpy for the following reaction: N2Ha(1) + 2H2O2(1) → N2(g) + 4H2O(I)…

Q: A 100.0 g piece of metal at 100°C is placed in contact with 50.0 g of water (s = 4.184 J g–1 °C–1)…

Q: Given the standard enthalpy changes for the following two reactions (1) 4C(s) + 5H2(g)–C,H10(g) AH°…

A: If the given reaction is multiplied by 2 by two, then value of the given standard enthalpy change…

Q: 2Cu +S(s)Cu2S(s) AH° = -79.5 kJ S(s) + O2(g)→ SO2(g) AH° = -297 kJ Cu,S(s) +202(g)→2CUO(s) +SO,lg)…

Q: What is the change in heat, in kJ, at 25 °C and 1 atm for the reaction of 2.00 mol of solid iron…

A: Since for the above reaction, ΔH° is the amount of heat change when 4 moles of Fe reacts at standard…

Q: H2(g) + F2(g) → 2 HF(g) ΔH = -542 kJ What would be the enthalpy change for the reverse of the…

A: Since, The standard enthalpy of the formation is defined as change of enthalpy of 1 mol of the…

Q: calculate the change in enthalpy for Reaction 2. Reaction 1:…

A: Given Reaction 1: C3H8(g) + 5O2(g)→3CO2(g) + 4H2O(g) ∆H1 = -2043 kJ mol-1 Reaction 2: 6C3H8(g) +…

Q: Calculate the standard enthalpy change for the reaction: 2C3H18(1) + 1702(g) ® 16CO(g) + 18H,O(1)…

A: When a thermochemical equation is reversed then its ∆H value chages its sign. When a thermochemical…

Q: Given the following enthalpy change values for the reactions below: A + B → 2C ; ΔrH = 169.9 kJ…

A: Given thermochemical equations are A + B → 2C ; ΔrH = 169.9 kJ mol-1 ------ (i) C + 2D → E + F ;…

Q: 4. Calculate A H for S (s) +0,(9) → so;(g) based on the reactions: S (s) + 02 → S02 (g) 2502 (g) +…

A: Given, S (s) + O2 → SO2 (g); ∆H = - 296 kJ .......(1) 2SO2(g) + O2(g) → 2SO3 (g); ΔΗ =-198.2…

Q: CH4 (9) + 20, (9) → CO2(9) + 2H,0(1) AH=-891 kJ a. Calculate the enthalpy change if 2.80 g methane…

Q: Given the standard enthalpy changes for the following two reactions: 2Pb+O2=2PbO 2Hg+O2=2H2O delta…

A: Standard enthalpy change for the following two reactions:1) 2Pb(s) + O2(g) ----> 2PbO(s) ∆H° =…

Q: Use the Standard Enthalpies of Formation given to solve for the AHf for C2H6. 2 C2H6 (g) + 7 O2(g)…

A: 2C2H6(g) +7O2(g) --> 4CO2(g) + 6H2O(g)

Q: Calculate the standard enthalpy of reaction for the process 2 NO,(9) + 7 H,(9) → 2 NH,(g) + 4 H,0(g)…

A: The standard enthalpy of reaction is the difference between total prodcut and total reactant…

Q: Calculate enthalpy change using standard heats of formation. Using the standard heats of formation…

A: The enthalpy change of a chemical reaction can be calculated by the standard heat of the formation…

Q: Using the standard enthalpies of formation: CO(g) = -103.9 kJ mol-1 CO(NH2)2(s) = -334.94 kJ mol-1…

A: Answer:- This question is answered by using the simple concept of calculation of enthalpy of…

Q: The standard enthalpy change for the following reaction is -104 kJ at 298 K. 3 C(s,graphite) +4…

Q: The following thermochemical equations are provided; C2H2 (g) + O2 (g) --> 2 CO2 (g) + H2O (l)…

A: According to Hess's law of thermodynamics, if a reaction proceeds through the multi-steps, then…

Q: Given the thermochemical equations X, +3 Y, → 2XY AH = -330 kJ X, +2Z, → 2XZ, AH = -120 kJ 2Y, +Z, →…

A: Given thermochemical reactions are : X2+3Y2→2XY3 ∆H1=-330 kJ…

Q: PCI5(s) can be prepared by the reaction PCI3(1) + Cl2(g) - PCI5(s). Calculate the enthalpy change…

Q: C4H100 C4H8 + H20. Use the data below to calculate the change in enthalpy for the above reaction.…

Q: Given the following enthalpy change values for the reactions below: A + B → 2C ; ΔrH = 305.5 kJ…

A: According to the Hess's law we know that when a chemical equation is written as the sum of overall…

Q: ) Calculate the standard enthalpy of reaction 4 using the given data: A(g)+X2(g)⟶AX2(g)…

A: The Heat of Reaction (also known and Enthalpy of Reaction) is the change in the enthalpy of a…

Q: Given the thermochemical equations X2+3Y2⟶2XY3 Δ?1=−390 kJ X2+2Z2⟶2XZ2…

A: Given: (1) X2 + 3Y2⟶ 2XY3 .........1 Δ?1=−390 kJ (2) X2 + 2Z2⟶ 2XZ2 ...............2…

Q: 16. Calculate the enthalpy for this reaction: 2C(s) + H2(g) - Given the following thermochemical…

Q: Use the balanced thermochemical equations shown below (reactions 1,2, & 3) to determine the enthalpy…

A: Solid magnesium react with oxygen and produced solid magnesium oxide

Q: 2A(S) + 2B(s) -> 2C(S) + D(g) Calculate reaction enthalpy in kJ given the following: X(s)…

A: Given, X(s) +1/2D(g)->A(s) H1= -379kJ Y(g) + B(s) -> Z(g) H2= -37kJ X(s) + Z(g)…

Q: Given the following enthalpy change values for the reactions below: A + B → 2C; AH = 286.5 kJ mol-1…

A: Given A + b → 2C ; ΔrH = 286.5 kJ/mol C + 2D → E + F; ΔrH = 41.8 kJ/mol H → (1/2)E + G ; ΔrH = 41.8…

Q: Given the thermochemical equations X₂ + 3Y₂ → ->> 2XY, X₂ +2Z₂ → 2XZ₂ ΔΗ, = -160 kJ 2Y₂+Z₂2Y₂Z AH3 =…

A: Given, a) X2 + 3 Y2 -----> 2 XY3 ∆H1 = -320 kJ b) X2 + 2 Z2 -----> 2 XZ2 ∆H2 = -160 kJ c) 2…

Q: Given the thermochemical equation 2A+B⟶3C+DΔ?=293 kJ determine the enthalpy change, Δ?,ΔH, for…

Q: For the chemical reaction Ca (s) + ½ O, (g) → CaO (s) AH° = -635 kJ/mol. What is the enthalpy for…

A: The given reaction is, 2CaO(s) ---> 2Ca(s) + O2(g) The chemical reaction given is, 1) Ca(s) +…

Q: Given the thermochemical equations X2+3Y2⟶2XY3. Δ?1=−340 kJ X2+2Z2⟶2XZ2 Δ?2=−190…

Q: Heat, q, is energy transferred between a system and its surroundings. For a process that involves a…

Q: Given the thermochemical equations X₂ + 3 Y₂ → 2XY3 X₂ +2Z₂ → 2XZ₂ 2Y₂+Z₂2Y₂Z AH3= -270 kJ Calculate…

A: The thermochemical equations are:The target equation is:To find, the value of .

Q: Given the thermochemical equations X, +3 Y, – 2XY3 AH1 = -380 kJ X, +2Z, ► 2 XZ, AH2 = -110 kJ 2 Y,…

Q: What is the change in the enthalpy (in kJ) for the complete combustion of 39.0 g of fructose,…

A: Heat of reaction or enthalpy change∆Hrxn is defined as heat released and absorbed during a reaction.…

Q: Given the thermochemical equations X, + 3 Y, → 2XY, AH1 = -390 kJ %3D X, + 2Z, → 2 XZ, AH2 = -120 kJ…

A: We have to calculate the enthalpy change for given reaction.

Q: Given the thermochemical equations X, +3 Y, - → 2XY; AH1 = -330 kJ X, + 2Z, 2 XZ, AH2 = -190 kJ %3D…

A: Given data is as follows: X2 + 3Y2 → 2XY3 ∆H1=-330 kJ ...... (1)…

Q: THERMODYNAMICS: Calculate the value of AH (in kJ) for the reaction, 2AR3 (g) + Q (s) → A2R4 (g) +…

Q: Using the equations Ca(s) + 1/2 O, (g) → CaO (s) AH° = -450 kJ/mol CO, (g) → C (s) + O, (g) AH° =…

Q: Given the following reaction and enthalpy value: H2(g) + I2(g) -> 2HI(g) deltaH = +52.96 kJ…

A: we know that enthalpy is additive in nature means when reaction add then enthalpy of reaction also…

Q: Using standard heats of formation, calculate the standard enthalpy change for the following…

A: Solution: Standard enthalpy of formation is the difference in the enthalpy of formation…

Question

Given the thermochemical equations
X, + 3 Y, → 2XY3
ΔΗ
= -390 kJ
-
X, + 2Z, → 2 XZ,
AH2 = -120 kJ
%3D
2 Y, + Z, → 2 Y,Z
AH3 = -240 kJ
Calculate the change in enthalpy for the reaction.
4 XY, + 7Z, –→ 6 Y,Z + 4 XZ,
ΔΗ

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

For the reaction below (which will be labeled reaction A), the reaction enthalpy is unknown: 2 B + 3 H2 B2H6 HA = ? Use the following thermochemical data to calculate the reaction enthalpy ΔHA: Reaction 1: 4 B + 3 O2 → 2 B2O3 ΔH1 = –2509 kJ Reaction 2: 2 H2 + O2 → 2 H2O ΔH2 = –572 kJ Reaction 3: B2H6 + 3 O2 → B2O3 + 3 H2O ΔH3 = –2,159 kJ Calculate the enthalpy of reaction A (in kJ) and enter the numerical value in the answer box. Do not write units in the answer box. Clearly show on a paper how each reaction can be combined to equal reaction A (multiply or reverse each of the above reactions).complete work must be uploaded
find the change in enthalpy for the reaction below. given the following reactions and change in enthalpy values: 2 C2H4O(I) + 3 O2(g) --> 2 CO2(g) + 3 H2O(I) ▲H= ??
(c) Consider the following chemical reaction: C;Hs(g) + H2(g) C2H6(g) + CH4(g) ΔΗ? %3D Calculate the enthalpy change for the reaction above using Hess's law. Thermochemical dat: H:(g) + ½O2(g) H2O(1) AH° =-285.8 kJ AH°combustion for CH4(g) AH° =-890.0 kJ/mol %3D CO:(g) C(s. graphite) + O:(g) AH° = +393.5 kJ AH°combustion for C2H6(g) AH = -1560.0 kJ/mol AH°, for C3H$(g) AH° =-103.8 kJ/mol
Given the following thermochemical equations: C2H29) + 5 02(9) 2C02(g) + H201) AH° = -1229.5 kJ AH° = -393.5 kJ C(6) + 02(g) → C02(g) 1 H2(9) +5 02(9) → H20) AH° = -285.5 kJ 2 Calculate the enthalpy (in kJ) for this reaction: 206) + H2(g) → C,H2(9)
Calcium acetate, Ca(CH3COO)2 has a molar mass of 158.17 g/mol. In a constant pressure calorimeter, 44.2 g of Ca(CH3COO)2 is dissolved in 861g of water at 25.00 °C. The heat produced by the solution was determined to be 15kJ. What is the final temperature of the solution? q= - msAT SH20 = 4.184 29.0 °C O 18.4 °C O 64.6 °C O 33.8 °C O 3.96 °C O 21.0 °C
Substance SiO,(s) SICLO H,O) HCIE) AH°, (kJ/mol) -910.7 -687.0 -285.83 -92.307 Calculate the standard enthalpy change for the following reaction: SICI4(1) + 2H20(1) → SIO2 (s) + 4HCI (g)
to calculate the true enthalpies of these reactions by the Hess’ law, as: ΔH°(rxn) = Σ[ν × ΔHf°(product)] – Σ[ν × ΔHf°(reactant)] for: Mg(s) + ½O2(g) → MgO(s)
(fHydrogen cyanide, a useful intermediate in the production of other pharmaceuticals and other chemicals, can be be prepared according to the following reaction: CH4(g) + NH3(g) ⟶⟶ HCN(g) + 3 H2(g). ΔΔHrxn= ???? Use the information provided to calculate the change in enthalpy for this reaction N2(g) + 3 H2(g) ⟶⟶ 2 NH3(g). ΔΔHrxn= -91.8 kJ/mol C(s) + 2 H2(g) ⟶⟶ CH4(g). ΔΔHrxn= -74.9 kJ/mol H2(g) + 2 C(s) + N2(g) ⟶⟶ 2 HCN(g) ΔΔHrxn= +270.3 kJ/mol
PCI5(s) can be prepared by the reaction PCI3(1) + Cl2(g) - PCI5(s). Calculate the enthalpy change (in kJ) that accompanies the production of 100.0 g of PCI5(s) by the above reaction, given the following data. P4(s) + 6 Cl2(g) - 4 PC|3(1) AH° = -1280 kJ per mole of P4(s) %3D P4(s) + 10 Cl2(g) – 4 PCI5(s) ΔΗ AH° = -1774 kJ per mole of P4(s) +59.3 -59.3 +124 -124 -258
Given the thermochemical equations X, + 3 Y, → 2XY; AH| = -370 kJ X, + 2Z, → 2 XZ, AH2 = -180 kJ 2 Y, + Z, → 2Y,Z AH3 = -220 kJ Calculate the change in enthalpy for the reaction. 4XY, + 7Z, → 6 Y,Z + 4 XZ, ΔΗ- kJ
Use the thermochemical equations shown below to determine the enthalpy for the reaction: C3H8(g) + 502(g) +3CO 2 + 4H2O(1) CO2 C(graphite) + 02 HE = 221.6KJ H2(g) + 1/2O2(g) H2O(1) HE= -160.3KJ 3 C(graphite) + 4 H2(g) C3H8(g) HE= -58.5KJ
Hess's Law Given the following data: 4C(s) + 3H2(g) + 1/2O2(g) → HCOC(CH2)(CH3)(l) ΔH°=-139.0 kJ CH3CH2OH(l) + 1/2O2(g) → CH3CHO(l) + H2O(l) ΔH°=-204.0 kJ 2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l) ΔH°=-278.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°=-286.0 kJ calculate ΔH° for the reaction:2CH3CHO(l) → HCOC(CH2)(CH3)(l) + H2O(l)