Given the thermochemical equations X, +3 Y, – 2XY3 AH1 = -380 kJ X, +2Z, ► 2 XZ, AH2 = -110 kJ 2 Y, + Z, → 2 Y,Z AH3 = -280 kJ Calculate the change in enthalpy for the reaction. 4XY, + 7Z, - > 6 Y,Z + 4XZ, ΔΗ kJ
Given the thermochemical equations X, +3 Y, – 2XY3 AH1 = -380 kJ X, +2Z, ► 2 XZ, AH2 = -110 kJ 2 Y, + Z, → 2 Y,Z AH3 = -280 kJ Calculate the change in enthalpy for the reaction. 4XY, + 7Z, - > 6 Y,Z + 4XZ, ΔΗ kJ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Given the thermochemical equations:
\[
X_2 + 3Y_2 \rightarrow 2XY_3 \quad \Delta H_1 = -380 \, \text{kJ}
\]
\[
X_2 + 2Z_2 \rightarrow 2XZ_2 \quad \Delta H_2 = -110 \, \text{kJ}
\]
\[
2Y_2 + Z_2 \rightarrow 2Y_2Z \quad \Delta H_3 = -280 \, \text{kJ}
\]
Calculate the change in enthalpy for the reaction:
\[
4XY_3 + 7Y_2 \rightarrow 6Y_2Z + 4XZ_2
\]
\[
\Delta H = \underline{\hspace{2cm}} \, \text{kJ}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F949aec52-a49c-42f0-a64a-572f49f7edd9%2Fa296d0c5-54dd-49b2-a676-90253f50cf37%2Fdv50jre_processed.png&w=3840&q=75)
Transcribed Image Text:Given the thermochemical equations:
\[
X_2 + 3Y_2 \rightarrow 2XY_3 \quad \Delta H_1 = -380 \, \text{kJ}
\]
\[
X_2 + 2Z_2 \rightarrow 2XZ_2 \quad \Delta H_2 = -110 \, \text{kJ}
\]
\[
2Y_2 + Z_2 \rightarrow 2Y_2Z \quad \Delta H_3 = -280 \, \text{kJ}
\]
Calculate the change in enthalpy for the reaction:
\[
4XY_3 + 7Y_2 \rightarrow 6Y_2Z + 4XZ_2
\]
\[
\Delta H = \underline{\hspace{2cm}} \, \text{kJ}
\]
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