Given the same reactant concentrations, the reaction CO(g) + Cl₂(g) →→→ COCL₂(g) at 250°C is 1.50 x 10' times as fast as the same reac- tion at 150°C. Calculate the activation energy for this reaction. Assume that the frequency factor is constant.

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Given the same reactant
concentrations, the reaction
CO(g) + Cl₂(g) → COCH₂(g)
at 250°C is 1.50 x 10' times as fast as the same reac-
tion at 150°C. Calculate the activation energy for this
reaction. Assume that the frequency factor is constant.
Transcribed Image Text:Given the same reactant concentrations, the reaction CO(g) + Cl₂(g) → COCH₂(g) at 250°C is 1.50 x 10' times as fast as the same reac- tion at 150°C. Calculate the activation energy for this reaction. Assume that the frequency factor is constant.
Expert Solution
Step 1

The relationship between rate constant and temperature is given by Arrhenius equation 

k = Ae-Ea/RT 

At two different temperatures the above equation can be written as 

logk2k1 = Ea2.303RT2-T1T1T2

Ea = Activation energy 

R = gas constant = 8.314 J/K.mol 

 

 

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