Given the reaction below, if 23.5 moles ammonia forms, how many moles of ammonium carbonate decomposed? (NH4)2CO3 (s) → 2 NH3 (g) + CO2 (g) + H2O (g)
Given the reaction below, if 23.5 moles ammonia forms, how many moles of ammonium carbonate decomposed?
(NH4)2CO3 (s) → 2 NH3 (g) + CO2 (g) + H2O (g)
The chemical equation to form ammonia by decomposition of ammonium carbonate is
(NH4)2CO3 (s) ----> 2 NH3 (g) + CO2 (g) + H2O (g)
From this chemical equation looking at the stoichiometric coefficient of reactant and product we can say that 1 mol of ammonium carbonate decomposed to form 2 mol of ammonia. so lets X mol of ammonium carbonate decomposed to form 23.5 mol of ammonia
1 mol of (NH4)2CO3 = 2 mol of NH3
so X mol of (NH4)2CO3 = 23.5 mol of NH3
on cross multiplying we get,
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
