Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol (CH3OH) by the following reaction. (There are two C=O double bonds in CO2) CO2(g) + 3 H2(g) → CH3OH(g) + H2O(g) B.E.C–O = 300 kJ/mol B.E.C=O = 700 kJ/mol B.E.H–H = 450 kJ/mol B.E.H–O = 500 kJ/mol
Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
Given the listed average bond energies (BE), calculate the enthalpy change for the production of one mole of methanol (CH3OH) by the following reaction. (There are two C=O double bonds in CO2)
CO2(g) + 3 H2(g) → CH3OH(g) + H2O(g)
B.E.C–O = 300 kJ/mol
B.E.C=O = 700 kJ/mol
B.E.H–H = 450 kJ/mol
B.E.H–O = 500 kJ/mol
B.E.H–C = 400 kJ/mol
-250 kJ
-950 kJ
950 kJ
50 kJ
250 kJ
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