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Given the linear equation y-5x = 6. Which statements are correct? A) The slope of the given equation is -5. B) The slope of a line perpendicular to the given line is The equation of a line parallel to the given line that passes through the point (3,10) is y = 5x - 5. C) The equation of a line perpendicular to the given line that passes through D) 1 53 the point (3,10) is y = -x+ 5 E) The slope-intercept form of the given equation is y = -5x + 6.

Given the linear equation y-5x = 6. Which statements are correct? A) The slope of the given equation is -5. B) The slope of a line perpendicular to the given line is The equation of a line parallel to the given line that passes through the point (3,10) is y = 5x - 5. C) The equation of a line perpendicular to the given line that passes through D) 1 53 the point (3,10) is y = -x+ 5 E) The slope-intercept form of the given equation is y = -5x + 6.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Given the linear equation y - 5x = 6, which statements are correct?** A) The slope of the given equation is -5. B) The slope of a line perpendicular to the given line is -\(\frac{1}{5}\). C) The equation of a line parallel to the given line that passes through the point (3,10) is y = 5x - 5. D) The equation of a line perpendicular to the given line that passes through the point (3,10) is y = -\(\frac{1}{5}\)x + \(\frac{53}{5}\). E) The slope-intercept form of the given equation is y = -5x + 6. --- There is no graph or diagram included in this transcription.
Transcribed Image Text:**Given the linear equation y - 5x = 6, which statements are correct?** A) The slope of the given equation is -5. B) The slope of a line perpendicular to the given line is -\(\frac{1}{5}\). C) The equation of a line parallel to the given line that passes through the point (3,10) is y = 5x - 5. D) The equation of a line perpendicular to the given line that passes through the point (3,10) is y = -\(\frac{1}{5}\)x + \(\frac{53}{5}\). E) The slope-intercept form of the given equation is y = -5x + 6. --- There is no graph or diagram included in this transcription.
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