Given the functions: 1. y = 0.1sin((x+0.15)/-0.1) +0.1 2. 6y=x^2-10 Find the area of the region bounded by the functions. (integral)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Given the functions:

1. y = 0.1sin((x+0.15)/-0.1) +0.1

2. 6y=x^2-10

Find the area of the region bounded by the functions. (integral)

 

+
x + 0.15
y = 0.1 sin
+0.1
-0.1
N 6y = x – 10
3
Transcribed Image Text:+ x + 0.15 y = 0.1 sin +0.1 -0.1 N 6y = x – 10 3
Expert Solution
Step 1

Let R be the region bounded by the curves y=0.1sinx+0.15-0.1+0.1and 6y=x2-10 the region is shown in the graph given below

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