Find the area under the curve y = 1/(6³) from x = 1 to x = t and evaluate it for t = 10, t = 100. Then find the total area under this curve for x ≥ 1. (a) t = 10 (b) t = 100 (c) Total area

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the area under the curve \( y = \frac{1}{6x^3} \) from \( x = 1 \) to \( x = t \) and evaluate it for \( t = 10 \), \( t = 100 \). Then find the total area under this curve for \( x \geq 1 \).

**Options:**

(a) \( t = 10 \)

[Checkbox]

(b) \( t = 100 \)

[Checkbox]

(c) Total area

[Checkbox]
Transcribed Image Text:**Problem Statement:** Find the area under the curve \( y = \frac{1}{6x^3} \) from \( x = 1 \) to \( x = t \) and evaluate it for \( t = 10 \), \( t = 100 \). Then find the total area under this curve for \( x \geq 1 \). **Options:** (a) \( t = 10 \) [Checkbox] (b) \( t = 100 \) [Checkbox] (c) Total area [Checkbox]
Expert Solution
Step 1: Define the problem.

To find the area under the curve straight y equals fraction numerator 1 over denominator 6 straight x cubed end fraction space from space straight x equals 1 space to space straight x equals straight t 

and to evaluate it for straight t equals 10 comma space straight t equals 100. Then to find the total area 

under this curve for straight x greater or equal than 1.

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