Given the function shown, complete the table and Graph using ONLY two pts f(x) 10+ 8- -6- f(x)=2x-1 x -3 -1 1 3
Given the function shown, complete the table and Graph using ONLY two pts f(x) 10+ 8- -6- f(x)=2x-1 x -3 -1 1 3
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
![### Completing the Table and Graphing the Function
#### Given the Function:
\[ f(x) = 2x - 1 \]
#### Objective:
Complete the table and graph the function using only two points.
### Table Completion:
| \( x \) | \( f(x) \) |
|----------|-------------|
| \(-3\) | |
| \(-1\) | |
| \(1\) | |
| \(3\) | |
1. To find \( f(x) \) for \( x = -3 \):
\[ f(-3) = 2(-3) - 1 = -6 - 1 = -7 \]
2. To find \( f(x) \) for \( x = -1 \):
\[ f(-1) = 2(-1) - 1 = -2 - 1 = -3 \]
3. To find \( f(x) \) for \( x = 1 \):
\[ f(1) = 2(1) - 1 = 2 - 1 = 1 \]
4. To find \( f(x) \) for \( x = 3 \):
\[ f(3) = 2(3) - 1 = 6 - 1 = 5 \]
So the completed table should look like:
| \( x \) | \( f(x) \) |
|----------|-------------|
| \(-3\) | \(-7\) |
| \(-1\) | \(-3\) |
| \(1\) | \(1\) |
| \(3\) | \(5\) |
### Graphing the Function:
1. **Plotting the Points**:
- Plot point \((-3, -7)\)
- Plot point \((-1, -3)\)
- Plot point \((1, 1)\)
- Plot point \((3, 5)\)
2. **Drawing the Line**:
- Since the function \( f(x) = 2x - 1 \) is linear, draw a straight line passing through the plotted points.
#### Graph Description:
- The graph is on a coordinate plane ranging from \(-10\) to \(10\) on both the \(x\)-axis and \(y\)-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc105c77f-9f91-4cd1-b0db-b6182cafb96d%2F8b9c78ff-bd1e-4a94-93c5-811038ad9c51%2Fo3zgb4_processed.png&w=3840&q=75)
Transcribed Image Text:### Completing the Table and Graphing the Function
#### Given the Function:
\[ f(x) = 2x - 1 \]
#### Objective:
Complete the table and graph the function using only two points.
### Table Completion:
| \( x \) | \( f(x) \) |
|----------|-------------|
| \(-3\) | |
| \(-1\) | |
| \(1\) | |
| \(3\) | |
1. To find \( f(x) \) for \( x = -3 \):
\[ f(-3) = 2(-3) - 1 = -6 - 1 = -7 \]
2. To find \( f(x) \) for \( x = -1 \):
\[ f(-1) = 2(-1) - 1 = -2 - 1 = -3 \]
3. To find \( f(x) \) for \( x = 1 \):
\[ f(1) = 2(1) - 1 = 2 - 1 = 1 \]
4. To find \( f(x) \) for \( x = 3 \):
\[ f(3) = 2(3) - 1 = 6 - 1 = 5 \]
So the completed table should look like:
| \( x \) | \( f(x) \) |
|----------|-------------|
| \(-3\) | \(-7\) |
| \(-1\) | \(-3\) |
| \(1\) | \(1\) |
| \(3\) | \(5\) |
### Graphing the Function:
1. **Plotting the Points**:
- Plot point \((-3, -7)\)
- Plot point \((-1, -3)\)
- Plot point \((1, 1)\)
- Plot point \((3, 5)\)
2. **Drawing the Line**:
- Since the function \( f(x) = 2x - 1 \) is linear, draw a straight line passing through the plotted points.
#### Graph Description:
- The graph is on a coordinate plane ranging from \(-10\) to \(10\) on both the \(x\)-axis and \(y\)-
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