Given the function ƒ, evaluate ƒ(−1), ƒ (0), ƒ (2), and ƒ (4). ƒ(−1) = Number f(x)= { x²-1 4+x-6| if x < 2 if x > 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Given the function f, evaluate f(-1), ƒ (0), ƒ (2), and f (4).
ƒ(−1) = Number
f(0) =
ƒ (2) =
ƒ (4) =
Number
Number
Number
={₁
f(x)=
x² 1
4+ x - 6|
if x < 2
if x ≥ 2
Transcribed Image Text:Given the function f, evaluate f(-1), ƒ (0), ƒ (2), and f (4). ƒ(−1) = Number f(0) = ƒ (2) = ƒ (4) = Number Number Number ={₁ f(x)= x² 1 4+ x - 6| if x < 2 if x ≥ 2
Expert Solution
Step 1: Define the problem

The given function is f open parentheses x close parentheses equals open curly brackets table row cell x squared minus 1 end cell cell i f space x less than 2 end cell row cell 4 plus open vertical bar x minus 6 close vertical bar end cell cell i f space x greater or equal than 2 end cell end table close

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