Given the function: (1x₁4) = log1 _log (x² - 3(4+2)) x+4- Domain: Denominator can not be fero X+41+0 x+y #1 and input to legarithm Junction S01 x ² - 3 14+2) So or Domain': x²-34-6 > 0 -3y > -x²+6 Multiplying by 1-1 to both sides 34 < x²-6. 6 ។ 4 c of (x, 4) ER² : x+y #1 and 4²x²2/6 3 of [x₁4) ER²: x+y #1, and x² > 34+67 4 x²-6 3 2 can not be negative 4 x+y #1 22 > 31472) Range Range of this function. X can not be defined.
Given the function: (1x₁4) = log1 _log (x² - 3(4+2)) x+4- Domain: Denominator can not be fero X+41+0 x+y #1 and input to legarithm Junction S01 x ² - 3 14+2) So or Domain': x²-34-6 > 0 -3y > -x²+6 Multiplying by 1-1 to both sides 34 < x²-6. 6 ។ 4 c of (x, 4) ER² : x+y #1 and 4²x²2/6 3 of [x₁4) ER²: x+y #1, and x² > 34+67 4 x²-6 3 2 can not be negative 4 x+y #1 22 > 31472) Range Range of this function. X can not be defined.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
TRANSCRIBE IN DIGITAL FORMTA THE FOLLOWING PROBLEM (WITH THE GRAPH IN DIGITAL FORMAT)
![Given the function:
f(x+4)
Domain: Denominator can not be ferro
x+y+ #0
x+y $1
and
or
log (x² - 3(4+2))
x+4-1
input to legarithm Junction can not be negative
Soi
x² - 3 14+2) So
1
Domain:
x²-34-6 > O
-34 > -x²+6t
Multiplying by 1-1 to both sides
2.-6.
зус
6
ус
of [x₁4) ER² : x+y #1 and 4² x ²2 6 4
of [x₁4] ER²: x+y #1, and x² > 34+67
4 2
4
Range! Range
2
-2² > 3 (4+2)
g
2
x²-6
3
this
4
6
x+y #1
function
x
can not be defined.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5bd84e3-a3d4-4208-8bff-a7bb4ed5a810%2F34b2560d-889b-4bcf-9e42-ea7c1580af57%2Fy8bfa8e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the function:
f(x+4)
Domain: Denominator can not be ferro
x+y+ #0
x+y $1
and
or
log (x² - 3(4+2))
x+4-1
input to legarithm Junction can not be negative
Soi
x² - 3 14+2) So
1
Domain:
x²-34-6 > O
-34 > -x²+6t
Multiplying by 1-1 to both sides
2.-6.
зус
6
ус
of [x₁4) ER² : x+y #1 and 4² x ²2 6 4
of [x₁4] ER²: x+y #1, and x² > 34+67
4 2
4
Range! Range
2
-2² > 3 (4+2)
g
2
x²-6
3
this
4
6
x+y #1
function
x
can not be defined.
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