Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential. Pb2*(ag) + 2 e-→ Pb(s) E° = -0.126 V Fe+(ag) + e→ Fe2*(s) E° = +0.771 V O a. Pb(s) + 2 Fe3*(aq) → Pb²*(aq) + 2 Fe2*(s); E°cell = +1.416 V
Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential. Pb2*(ag) + 2 e-→ Pb(s) E° = -0.126 V Fe+(ag) + e→ Fe2*(s) E° = +0.771 V O a. Pb(s) + 2 Fe3*(aq) → Pb²*(aq) + 2 Fe2*(s); E°cell = +1.416 V
Chemistry
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ISBN:9781305957404
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![Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential.
Pb2+(ag) + 2 e- Pb(s) E° =-0.126 V
Fe3+(aq) + e-→ Fe2+(s) E° = +0.771 V
O a. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2*(s); E°cell = +1.416 V
O b.Pb2+(aq) + 2 Fe²*(s) → Pb(s) + 2 Fe3+(aq); E°cell = +0.897 V
OC. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2*(s); E°cell = +0.897 V
O d. Pb(s) + Fe3+(aq)→ Pb2+(aq) + Fe2*(s); E°cell = +0.645 V
O e. Pb2+(aq) + Fe2*(s) → Pb(s) + Fe3+(aq); E°cell = +0.645 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea514ade-277c-4677-a71e-906815038818%2F3e18f393-38d9-476b-9eae-a71f87146dfd%2Faeabtg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential.
Pb2+(ag) + 2 e- Pb(s) E° =-0.126 V
Fe3+(aq) + e-→ Fe2+(s) E° = +0.771 V
O a. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2*(s); E°cell = +1.416 V
O b.Pb2+(aq) + 2 Fe²*(s) → Pb(s) + 2 Fe3+(aq); E°cell = +0.897 V
OC. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2*(s); E°cell = +0.897 V
O d. Pb(s) + Fe3+(aq)→ Pb2+(aq) + Fe2*(s); E°cell = +0.645 V
O e. Pb2+(aq) + Fe2*(s) → Pb(s) + Fe3+(aq); E°cell = +0.645 V
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