Given the following two half reactions write a balanced oxidation-reduction reaction that occurs between sulfite and Ru3+ in acidic solution. Recall that a good way to proceed is to balance each half reaction in acidic solution, adjust one or both to have the same number of electrons gained as lost, and then add them together .. SO32-→ SO42- and Ru3+ → Ru2+ A) H2O + SO3²- + Ru3+ Ru2+ + SO42- + 2H* B) 6 H2O + 2 SO32- + Ru3+ → Ru2+ + 2 SO42- + 12 H* C) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO42- + 2H* A) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO4²- + 2e¯ + 2H*

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Given the following two half reactions write a balanced oxidation-reduction reaction that occurs between
sulfite and Ru3+ in acidic solution. Recall that a good way to proceed is to balance each half reaction in acidic
solution, adjust one or both to have the same number of electrons gained as lost, and then add them together ..
SO32-→ SO42- and Ru3+ → Ru2+
A) H2O + SO3²- + Ru3+
Ru2+ + SO42- + 2H*
B) 6 H2O + 2 S032- + Ru3+ →
Ru2+ + 2 SO42- + 12 H*
C) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO42- + 2H*
A) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO4²- + 2e¯ + 2H*
Transcribed Image Text:Given the following two half reactions write a balanced oxidation-reduction reaction that occurs between sulfite and Ru3+ in acidic solution. Recall that a good way to proceed is to balance each half reaction in acidic solution, adjust one or both to have the same number of electrons gained as lost, and then add them together .. SO32-→ SO42- and Ru3+ → Ru2+ A) H2O + SO3²- + Ru3+ Ru2+ + SO42- + 2H* B) 6 H2O + 2 S032- + Ru3+ → Ru2+ + 2 SO42- + 12 H* C) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO42- + 2H* A) H2O + SO3²- + 2 Ru3+ → 2 Ru²+ + SO4²- + 2e¯ + 2H*
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