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Given the following two equilibria at 750 K. NiCO3 (s)  ⇔  Ni2+(aq)  +  CO32-(aq)                                          Kc = 6.6 x 10-9 HCO3- (aq)  +  H2O(liq.)  ⇔  CO32- (aq)  +  H3O+ (aq)               Kc = 4.8 x 10-11   Based on the above two equilibria, calculate the equilibrium constant for the following reaction at 750 K.   NiCO3(s) + H3O+ (aq) ⇔ Ni2+(aq) + HCO3- (aq) + H2O(liq.

Given the following two equilibria at 750 K. NiCO3 (s)  ⇔  Ni2+(aq)  +  CO32-(aq)                                          Kc = 6.6 x 10-9 HCO3- (aq)  +  H2O(liq.)  ⇔  CO32- (aq)  +  H3O+ (aq)               Kc = 4.8 x 10-11   Based on the above two equilibria, calculate the equilibrium constant for the following reaction at 750 K.   NiCO3(s) + H3O+ (aq) ⇔ Ni2+(aq) + HCO3- (aq) + H2O(liq.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Given the following two equilibria at 750 K.

NiCO3 (s)  ⇔  Ni2+(aq)  +  CO32-(aq)                                          Kc = 6.6 x 10-9

HCO3- (aq)  +  H2O(liq.)  ⇔  CO32- (aq)  +  H3O+ (aq)               Kc = 4.8 x 10-11

 

Based on the above two equilibria, calculate the equilibrium constant for the following reaction at 750 K.

 

NiCO3(s) + H3O+ (aq) ⇔ Ni2+(aq) + HCO3- (aq) + H2O(liq.

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