Given the following thermochemical equations with hypothetical ΔH values: 2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l) ΔH = -1,056 kJ 4NH3 (g) + 3O2 (g) → 2N2 (g) + 6H2O (l) ΔH = -1,549 kJ Calculate the value of ΔH (in kJ) for the reaction: N2 (g) + ½ O2 (g) → N2O (g)
Given the following thermochemical equations with hypothetical ΔH values: 2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l) ΔH = -1,056 kJ 4NH3 (g) + 3O2 (g) → 2N2 (g) + 6H2O (l) ΔH = -1,549 kJ Calculate the value of ΔH (in kJ) for the reaction: N2 (g) + ½ O2 (g) → N2O (g)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Given the following thermochemical equations with hypothetical ΔH values:
2NH3 (g) + 3N2O (g) → 4N2 (g) + 3H2O (l) ΔH = -1,056 kJ
4NH3 (g) + 3O2 (g) → 2N2 (g) + 6H2O (l) ΔH = -1,549 kJ
Calculate the value of ΔH (in kJ) for the reaction: N2 (g) + ½ O2 (g) → N2O (g)
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