Given the following thermochemical equations, 4B(s) + 3O2(g) → 2B2O3(s)                         ∆Ho= -2543.8 kJ H2 (g) + ½ O2(g) → H2O (g)                        ∆Ho= -241.8 kJ B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)   ∆Ho= -2032.9 kJ Which equation shows the decomposition of B2H6 into its elements?     B2H6(s)  → 2B (s) + 3H2 (g)     B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)     2B2O3(s)   →  4B(s) + 3O2(g)     B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)

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Given the following thermochemical equations,

4B(s) + 3O2(g) → 2B2O3(s)                         ∆Ho= -2543.8 kJ
H2 (g) + ½ O2(g) → H2O (g)                        ∆Ho= -241.8 kJ
B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)   ∆Ho= -2032.9 kJ

Which equation shows the decomposition of B2H6 into its elements?

   

B2H6(s)  → 2B (s) + 3H2 (g)

   

B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)

   

2B2O3(s)   →  4B(s) + 3O2(g)

   

B2H6(s) + 3O2(g) → B2O3(s) + 3H2O (g)

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