Given the following standard enthalpy change, use the standard enthalpies of formation in Table 5.3 to calculate the standard enthalpy of formation of CuO(s): CuO(s) + H2(8) – Cu(s) + H2O(1) AH = -129.7k) %3D

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**TABLE 5.3: Standard Enthalpies of Formation, ΔH⁰ₒ, at 298 K**

| Substance           | Formula     | ΔH⁰ₒ (kJ/mol) |
|---------------------|-------------|---------------|
| Acetylene           | C₂H₂(g)     | 226.7         |
| Ammonia             | NH₃(g)      | -46.19        |
| Benzene             | C₆H₆(l)     | 49.0          |
| Calcium carbonate   | CaCO₃(s)    | -1207.1       |
| Calcium oxide       | CaO(s)      | -635.5        |
| Carbon dioxide      | CO₂(g)      | -393.5        |
| Carbon monoxide     | CO(g)       | -110.5        |
| Diamond             | C(s)        | 1.88          |
| Ethane              | C₂H₆(g)     | -84.68        |
| Ethanol             | C₂H₅OH(l)   | -277.7        |
| Ethylene            | C₂H₄(g)     | 52.30         |
| Glucose             | C₆H₁₂O₆(s)  | -1273         |
| Hydrogen bromide    | HBr(g)      | -36.23        |
| Hydrogen chloride   | HCl(g)      | -92.30        |
| Hydrogen fluoride   | HF(g)       | -268.60       |
| Hydrogen iodide     | HI(g)       | 25.9          |
| Methane             | CH₄(g)      | -74.80        |
| Methanol            | CH₃OH(l)    | -238.6        |
| Propane             | C₃H₈(g)     | -103.85       |
| Silver chloride     | AgCl(s)     | -127.0        |
| Sodium bicarbonate  | NaHCO₃(s)   | -947.7        |
| Sodium carbonate    | Na₂CO₃(s)   | -1130.9       |
| Sodium chloride     | NaCl(s)     | -410.9        |
| Sucrose             | C₁₂H₂₂O
Transcribed Image Text:**TABLE 5.3: Standard Enthalpies of Formation, ΔH⁰ₒ, at 298 K** | Substance | Formula | ΔH⁰ₒ (kJ/mol) | |---------------------|-------------|---------------| | Acetylene | C₂H₂(g) | 226.7 | | Ammonia | NH₃(g) | -46.19 | | Benzene | C₆H₆(l) | 49.0 | | Calcium carbonate | CaCO₃(s) | -1207.1 | | Calcium oxide | CaO(s) | -635.5 | | Carbon dioxide | CO₂(g) | -393.5 | | Carbon monoxide | CO(g) | -110.5 | | Diamond | C(s) | 1.88 | | Ethane | C₂H₆(g) | -84.68 | | Ethanol | C₂H₅OH(l) | -277.7 | | Ethylene | C₂H₄(g) | 52.30 | | Glucose | C₆H₁₂O₆(s) | -1273 | | Hydrogen bromide | HBr(g) | -36.23 | | Hydrogen chloride | HCl(g) | -92.30 | | Hydrogen fluoride | HF(g) | -268.60 | | Hydrogen iodide | HI(g) | 25.9 | | Methane | CH₄(g) | -74.80 | | Methanol | CH₃OH(l) | -238.6 | | Propane | C₃H₈(g) | -103.85 | | Silver chloride | AgCl(s) | -127.0 | | Sodium bicarbonate | NaHCO₃(s) | -947.7 | | Sodium carbonate | Na₂CO₃(s) | -1130.9 | | Sodium chloride | NaCl(s) | -410.9 | | Sucrose | C₁₂H₂₂O
**Practice Exercise 2**

Given the following standard enthalpy change, use the standard enthalpies of formation in Table 5.3 to calculate the standard enthalpy of formation of CuO(s):

\[ \text{CuO(s) + H}_2\text{(g) → Cu(s) + H}_2\text{O(l)} \]

\[ \Delta H^\circ = -129.7 \text{ kJ} \]
Transcribed Image Text:**Practice Exercise 2** Given the following standard enthalpy change, use the standard enthalpies of formation in Table 5.3 to calculate the standard enthalpy of formation of CuO(s): \[ \text{CuO(s) + H}_2\text{(g) → Cu(s) + H}_2\text{O(l)} \] \[ \Delta H^\circ = -129.7 \text{ kJ} \]
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