3 3. Given the following reduction half-reactions:Zn2* (ag) + 2 eZn (s)E°red = -0.763 VPb?*(aq) + 2e →Pb(s)E°red = -0.126 Va) Which one is the anode? Which one is cathode?b) Calculate the E°.cell

Given Zn2+(aq) + 2e- → Zn(s) Ered0 = - 0.763 VPb2+(aq) + 2e- → Pb(s) Ered0 = - 0.126 V

Given the following reduction half-reactions: Zn2 (aq) + 2 e - Pb2*(aq) + 2e – Pb(s) E'red = -0.126 V Zn (s) E°red = -0.763 V a) Which one is the anode? Which one is cathode? b) Calculate the Eºcell

Given the following reduction half-reactions: Zn2 (aq) + 2 e - Pb2*(aq) + 2e – Pb(s) E'red = -0.126 V Zn (s) E°red = -0.763 V a) Which one is the anode? Which one is cathode? b) Calculate the Eºcell

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

3. Given the following reduction half-reactions:
Zn2* (ag) + 2 e
Zn (s)
E°red = -0.763 V
Pb?*(aq) + 2e →
Pb(s)
E°red = -0.126 V
a) Which one is the anode? Which one is cathode?
b) Calculate the E°.
cell

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