Given the following overall reaction, standard cell potential (E°cell), concentrations, and temperature; use the Nernst equation to calculate the actual cell potential (Ecell). 424 + 2 B(s) As) + 2 B*(aq) E°cell = 0.775 V %3D Conc. A2*a0) = 0.308 MA²+ %3D Conc. B"(aq) = 1.833 MB* Temperature = 16.76 °C %3D R = 8.314462 J/K-mol F = 96,485.34 C/mol e

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**Topic: Calculation of Actual Cell Potential Using the Nernst Equation**

Given the following overall reaction, standard cell potential (\(E^\circ_{\text{cell}}\)), concentrations, and temperature; use the Nernst equation to calculate the actual cell potential (\(E_{\text{cell}}\)).

**Reaction:**
\[ \text{A}^{2+}_{(aq)} + 2 \text{B}_{(s)} \rightarrow \text{A}_{(s)} + 2 \text{B}^{+}_{(aq)} \]

- Standard Cell Potential, \(E^\circ_{\text{cell}} = 0.775 \, \text{V}\)
- Concentration of \(\text{A}^{2+}_{(aq)} = 0.308 \, \text{M}\)
- Concentration of \(\text{B}^{+}_{(aq)} = 1.833 \, \text{M}\)
- Temperature = \(16.76^\circ \text{C}\)

Constants:
- \(R = 8.314462 \, \text{J/K} \cdot \text{mol}\)
- \(F = 96,485.34 \, \text{C/mol e}^-\)

**Instructions for Answer Submission:**

- Enter the number only (no units).
- Do not leave any spaces.
- Use a leading zero before the decimal when necessary.
- Report your number to 3 decimal places (regardless of the significant figures).
- Correctly round your answer to the 3rd decimal place (margin of allowed error is only \(\pm 0.001\), so always use un-rounded numbers in your calculations).

**Examples:**
- \(0.123\) or \(9.876\)
Transcribed Image Text:**Topic: Calculation of Actual Cell Potential Using the Nernst Equation** Given the following overall reaction, standard cell potential (\(E^\circ_{\text{cell}}\)), concentrations, and temperature; use the Nernst equation to calculate the actual cell potential (\(E_{\text{cell}}\)). **Reaction:** \[ \text{A}^{2+}_{(aq)} + 2 \text{B}_{(s)} \rightarrow \text{A}_{(s)} + 2 \text{B}^{+}_{(aq)} \] - Standard Cell Potential, \(E^\circ_{\text{cell}} = 0.775 \, \text{V}\) - Concentration of \(\text{A}^{2+}_{(aq)} = 0.308 \, \text{M}\) - Concentration of \(\text{B}^{+}_{(aq)} = 1.833 \, \text{M}\) - Temperature = \(16.76^\circ \text{C}\) Constants: - \(R = 8.314462 \, \text{J/K} \cdot \text{mol}\) - \(F = 96,485.34 \, \text{C/mol e}^-\) **Instructions for Answer Submission:** - Enter the number only (no units). - Do not leave any spaces. - Use a leading zero before the decimal when necessary. - Report your number to 3 decimal places (regardless of the significant figures). - Correctly round your answer to the 3rd decimal place (margin of allowed error is only \(\pm 0.001\), so always use un-rounded numbers in your calculations). **Examples:** - \(0.123\) or \(9.876\)
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