Given the following nuclear reaction: 252 Ese+ 4X 99 Column A 1. N 2. 3. 4. What is the atomic mass of the new atom? What is the atomic number of the new atom? What is the symbol of the new atom? What type of decay is demonstrated here? Column B a. 251 b. Gamma Decay c. 99 d. Md e. 253 f. Beta Decay 540
Given the following nuclear reaction: 252 Ese+ 4X 99 Column A 1. N 2. 3. 4. What is the atomic mass of the new atom? What is the atomic number of the new atom? What is the symbol of the new atom? What type of decay is demonstrated here? Column B a. 251 b. Gamma Decay c. 99 d. Md e. 253 f. Beta Decay 540
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given the following nuclear reaction
![### Understanding Nuclear Reactions
**Nuclear Reaction Given:**
\[ ^{252}_{99}Es \rightarrow ^{0}_{-1}e + ^{A}_{Z}X \]
### Match the Following
This exercise involves matching questions from Column A with the correct answers in Column B, based on the provided nuclear reaction.
#### Column A
1. **What is the atomic mass of the new atom?**
2. **What is the atomic number of the new atom?**
3. **What is the symbol of the new atom?**
4. **What type of decay is demonstrated here?**
#### Column B
a. 251
b. Gamma Decay
c. 99
d. Md
e. 253
f. Beta Decay
g. 101
h. 248
i. Alpha Decay
j. 252
k. 100
l. Fm
m. Es
### Explanation of Choices:
- **Atomic Mass:**
The atomic mass of the original atom (Einsteinium) is 252. Due to the beta decay (emission of a beta particle, \( ^{0}_{-1}e \)), the atomic mass of the new atom would remain roughly the same, as the emission of a beta particle does not significantly affect the mass number. Therefore, the atomic mass of the new atom is 252.
- **Atomic Number:**
The atomic number of the new atom increases by 1 due to beta decay (since a neutron is converted into a proton). The original atomic number of Einsteinium (Es) is 99. Therefore, the new atomic number is \( 99 + 1 = 100 \).
- **Symbol:**
Based on the increase in the atomic number from 99 (Es) to 100, the new symbol corresponds to the element with atomic number 100, which is Fermium (Fm).
- **Type of Decay:**
The given nuclear reaction shows the emission of a beta particle (\( ^{0}_{-1}e \)), indicating Beta Decay.
### Answers:
1. j. 252
2. k. 100
3. l. Fm
4. f. Beta Decay](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ad80e50-c954-4544-ab96-d220f1f8ae54%2F5a59e124-aa77-47c7-a580-7250bab69f6a%2F6xvlazj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Nuclear Reactions
**Nuclear Reaction Given:**
\[ ^{252}_{99}Es \rightarrow ^{0}_{-1}e + ^{A}_{Z}X \]
### Match the Following
This exercise involves matching questions from Column A with the correct answers in Column B, based on the provided nuclear reaction.
#### Column A
1. **What is the atomic mass of the new atom?**
2. **What is the atomic number of the new atom?**
3. **What is the symbol of the new atom?**
4. **What type of decay is demonstrated here?**
#### Column B
a. 251
b. Gamma Decay
c. 99
d. Md
e. 253
f. Beta Decay
g. 101
h. 248
i. Alpha Decay
j. 252
k. 100
l. Fm
m. Es
### Explanation of Choices:
- **Atomic Mass:**
The atomic mass of the original atom (Einsteinium) is 252. Due to the beta decay (emission of a beta particle, \( ^{0}_{-1}e \)), the atomic mass of the new atom would remain roughly the same, as the emission of a beta particle does not significantly affect the mass number. Therefore, the atomic mass of the new atom is 252.
- **Atomic Number:**
The atomic number of the new atom increases by 1 due to beta decay (since a neutron is converted into a proton). The original atomic number of Einsteinium (Es) is 99. Therefore, the new atomic number is \( 99 + 1 = 100 \).
- **Symbol:**
Based on the increase in the atomic number from 99 (Es) to 100, the new symbol corresponds to the element with atomic number 100, which is Fermium (Fm).
- **Type of Decay:**
The given nuclear reaction shows the emission of a beta particle (\( ^{0}_{-1}e \)), indicating Beta Decay.
### Answers:
1. j. 252
2. k. 100
3. l. Fm
4. f. Beta Decay
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