The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for 95% of the lead to decay? (Round your answer to two decimal places.)
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for 95% of the lead to decay? (Round your answer to two decimal places.)
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![The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for
95% of the lead to decay? (Round your answer to two decimal places.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccddceb6-96d6-484c-8378-6d8620562c07%2F251f682d-d7b5-4aeb-8239-37deb2cd7e21%2Fl9mgmx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.3 hours. If 1 gram of this isotope is present initially, how long will it take for
95% of the lead to decay? (Round your answer to two decimal places.)
Expert Solution
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Step 1
As radioactive decay is a first order process,
Rate of radioactive decay, r = k [N]1
So, integrated rate law equation is ln ([N]t/[N]o) = -t
[N]o is the initial number of nuclides present at time 0 = 1 g [100 %]
After decay of 95 % of Lead isotope, only 5 % of nuclides will be present
[N]t is the number of nuclides present at time t = 0.05 [ 5 % = 5/100]
half-life, t1/2 = 3.3 hrs
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