Given the following information for a simple spiraled curve: Da = 4°30'0O" o Ls = 800 feet o T.S. = Sta 35+00 Assuming the instrument is setup over the T.S. and the back-sight is set to 0°00'00" at the Pl. What deflection angle, to the nearest second, is required to set a point on the spiral at Station 40+95?

Given the following information for a simple spiraled curve: Da = 4°30'0O" o Ls = 800 feet o T.S. = Sta 35+00 Assuming the instrument is setup over the T.S. and the back-sight is set to 0°00'00" at the Pl. What deflection angle, to the nearest second, is required to set a point on the spiral at Station 40+95?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

purses / OID 310 674_GMT151_1 / 19 April - 25 April / MID-TERM EXAM Which one is wrong about traversing? O a. In closed polygon traverse both starting and terminating points of the traverse coincide with each other. O b. The intervisibility between adjacent stations, forward and back, must be maintained for angle and distance measurements. Oc Open traverses are strong in terms of eliminating errors and mistakes. O d. Interior angle traverses must be turned clockwise from the backsight site to the foresight site to reduce mistakes. e. A Traverse may be of two types: Open Traverse and Closed Traverse Next page
The bearing to the backsight is N65°E. The turning (horizontal) angle to a topographic shot is 173°. What is the bearing to said topographic shot? S72°E S18°W S32°E S58°W
lassroom.google.com/u/0/c/NDQ1NzgwNjY4OTkx/a/NDU3NDMONDU1NJU5/details Open with CURVATURE AND REFRACTION 3. Two hills 96.60 km apart, the higher being at a height of 274.39 m and the lower hill is at a height of 60.98 m. Determine the height of a tower located on top of the higher hill that can h = ? be seen from the lower hill. Line of sight Hill 2 h33D274.39 m Point of tangency k2 Hill 1 台 k1 k = 96.60 km %3D h, = 60.98 m 4. Page 4 / 5 IA 1:49 75°F Mostly clear 1/24
I need the answer as soon as possible
4. What is the interior angle at A? This is angle CAB - note that this angle is an angle to the right of clockwise. A N88°50'20"E N27°13′19″W S24°40′13″W B
What is the purpose of getting the bearing angle of the traverse line? To know the location of the traverse station. It is needed to get the forward length using the total station. It is needed to compute the elevation of the traverse station. It's fun.
Q4-In the traverse below if the Azimuth of AB = 30° 30' 30" find the coordinates of point B and C 70° 15' 15" 200m 58° 40' 40" A (15,15) Q5- For the closed looped traverse PQRS below, find:- 1. Closing error and relative accuracy. 2. The correct coordinate of Q and R points. (by using compass method) If known the computed coordinates of P, Q and R as shown below North(y) 3. The correct length and direction (AZ) of QR Iline. 20m points East(X) 45m 300.24 199.88 (200,300) 275 200 317.03 R R 144.02 25m 70m A30° 30' 30"
1. GIVEN THE FOLLOWING DATA, SOLVE FOR THE INTERIOR ANGLES OF A CLOSED TRAVERSE. (NOTE: DRAW THE CLOSE TRAVERSE GIVEN THE ANGLES AND LINES LINE FORE BEARING АВ 40°30' ВС 145°15' CD 52°32' DE 215°65' EF 304°87' 2. GIVEN THE FOLLOWING DATA, SOLVE FOR THE ADJUSTED/ CORRECTED ANGLES, AND EXTERIOR ANGLES (TABULATE YOUR ANSWERS) LINE INTERIOR ANGLE A 135°00' В 67°50' 125°00' D 31°55'
surveying. practical part:
16. Determine the unknown interior and deflection angles for the traverses shown in Figure 6-38. G Course Azim GH HI IG 80°39' 292°11' 142°38' H
The constant K and C for certain instrument were 99.81 and 0 respectively. The ground makes a uniform slope of 9.8% from point A to point B. With the instrument at A and staff at B, readings were taken but due to obstruction in the line of sight, only reading was recorded to be 1.99m if the vertical angle of the instrument was 6.49° and Height of instrument above A was 1.7m. Determine the horizontal distance between A and B.
C (A) 0°05'00" (B) 4°55'00" (C) 5°50'00" (D) 11°05'00" 100 ft Given intersection angle A = 22.5°, degree of curve D=4.5°, and the P.I. Station 72 +34.50 (1 station 100 feet). Using arc definition, deflection angle at Station 72+00.00 would be nearly: =