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Given the following half reactions with their corresponding standard reduction potentials, which of the following is/are true for the overall reaction happening under standard conditions? NO3 + 2H+ + 2e¯ → NO₂ + H₂O → 12 O₂ + 2H+ + 2e¯ H₂O (CHECK THE ONE(S) THAT IS/ARE CORRECT) E'º=0.421 V E'º=0.816 V 1) AE'° = 0.395 V for the spontaneous reaction. 2) 12 0₂ + NO₂ → NO3 is a spontaneous reaction. 3) 02 is the reducing agent. 4) NO₂ is the oxidizing agent. 5) AE'° = 1.237 V for the spontaneous reaction.

Given the following half reactions with their corresponding standard reduction potentials, which of the following is/are true for the overall reaction happening under standard conditions? NO3 + 2H+ + 2e¯ → NO₂ + H₂O → 12 O₂ + 2H+ + 2e¯ H₂O (CHECK THE ONE(S) THAT IS/ARE CORRECT) E'º=0.421 V E'º=0.816 V 1) AE'° = 0.395 V for the spontaneous reaction. 2) 12 0₂ + NO₂ → NO3 is a spontaneous reaction. 3) 02 is the reducing agent. 4) NO₂ is the oxidizing agent. 5) AE'° = 1.237 V for the spontaneous reaction.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 2 Given the following half reactions with their corresponding standard reduction potentials, which of the following is/are true for the overall reaction happening under standard conditions? NO3 + 2H+ + 2e¯ → NO₂ + H₂O ¹2 O₂ + 2H+ + 2e¯ → H₂O (CHECK THE ONE(S) THAT IS/ARE CORRECT) 1) AE'° = 0.395 V for the spontaneous reaction. 2) 12 O₂ + NO₂- E'º=0.421 V E'º=0.816 V → NO3 is a spontaneous reaction. 3) O2 is the reducing agent. 4) NO₂ is the oxidizing agent. 5) AE¹⁰ = 1.237 V for the spontaneous reaction.
Transcribed Image Text:Question 2 Given the following half reactions with their corresponding standard reduction potentials, which of the following is/are true for the overall reaction happening under standard conditions? NO3 + 2H+ + 2e¯ → NO₂ + H₂O ¹2 O₂ + 2H+ + 2e¯ → H₂O (CHECK THE ONE(S) THAT IS/ARE CORRECT) 1) AE'° = 0.395 V for the spontaneous reaction. 2) 12 O₂ + NO₂- E'º=0.421 V E'º=0.816 V → NO3 is a spontaneous reaction. 3) O2 is the reducing agent. 4) NO₂ is the oxidizing agent. 5) AE¹⁰ = 1.237 V for the spontaneous reaction.
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