Given the following function on lists: def foo : list A → list (list A) | [] := [[]] | (a :: as) := (a :: as) :: (foo as) Which of the following properties hold? i) ∀ xs : list A, ∃ ys : list (list A), ys = foo xs ii) ∀ ys : list (list A), ∃ xs:list A , ys = foo xs iii) ∀ xs : list A, ∃ yys : list (list A), foo xs = xs :: yys iv) ∀ xs ys : list A, foo (xs ++ ys) = foo xs ++ foo ys v) ∀ xs ys : list A, xs = ys → foo xs = foo ys vi) ∀ xs ys : list A, foo xs = foo ys → xs = ys You are not required to prove them

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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This question is concerned with Booleans and Lists using predicate logic in Lean

Given the following function on lists:


def foo : list A → list (list A)
| [] := [[]]
| (a :: as) := (a :: as) :: (foo as)


Which of the following properties hold?


i) ∀ xs : list A, ∃ ys : list (list A), ys = foo xs
ii) ∀ ys : list (list A), ∃ xs:list A , ys = foo xs
iii) ∀ xs : list A, ∃ yys : list (list A), foo xs = xs :: yys
iv) ∀ xs ys : list A, foo (xs ++ ys) = foo xs ++ foo ys
v) ∀ xs ys : list A, xs = ys → foo xs = foo ys
vi) ∀ xs ys : list A, foo xs = foo ys → xs = ys


You are not required to prove them

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