Given the following function header:def longest_chain(lst: list[int]) -> int:II II IIGiven a list of integers, return the length of the longest chain of 1'sthat start from the beginning.Precondition: 1st is non-emptyII II IIwhich one of the cases below is the least useful to check? Select the best answer.o longest_chain([0])o longest_chain([1, 1, O])o longest_chain([1, 1, 0, 1])o longest_chain([1, 0, 1, 1])o longest_chain(['1', '1', 'O', '1', '1', '1'])

Task :- choose the correct option for given question.

Answered: Given the following function header:…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Write a function called find_duplicates which accepts one list as a parameter. This function needs to sort through the list passed to it and find values that are duplicated in the list. The duplicated values should be compiled into another list which the function will return. No matter how many times a word is duplicated, it should only be added once to the duplicates list. NB: Only write the function. Do not call it. For example: Test Result random_words = ("remember","snakes","nappy","rough","dusty","judicious","brainy","shop","light","straw","quickest", "adventurous","yielding","grandiose","replace","fat","wipe","happy","brainy","shop","light","straw", "quickest","adventurous","yielding","grandiose","motion","gaudy","precede","medical","park","flowers", "noiseless","blade","hanging","whistle","event","slip") print(find_duplicates(sorted(random_words))) ['adventurous', 'brainy', 'grandiose', 'light', 'quickest', 'shop', 'straw', 'yielding']…
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The function count_contains_og in python takes a list of strings and returns how many strings in the list contain 'og' / 'OG' / 'oG' / 'Og' (check for 'og', ignoring case). Hint: Use the sequence membership operator in to help you check for 'og' in the individual strings. Create a lower-cased version of the string (lower), then use the in operator. For example: Test Result str_list = ['cat', 'dog', 'FROG', 'monkey'] print(count_contains_og(str_list)) 2 strlist = ["X", "x"] print(count_contains_og(strlist)) 0 list_of_one_og = ["Doggie"] print(count_contains_og(list_of_one_og)) 1
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I need to find the asnwer to this question I do have the code from the lab before I just need to know how to add that one to the other code. 3.9 LAB: Smallest and largest numbers in a list using min and max built-in functions NOTE1: Please make sure you complete previous lab successfully before you proceed with this Lab assignment NOTE2: Make sure to copy and past your code from previous lab into here and update it to complete this lab Write a program that reads a list of integers into a list as long as the integers are greater than zero, then outputs the list values and the smallest and largest integers in the list using min and max built-in functions . Ex: If the input is: 10 5 3 21 2 -6 the output is: [10, 5, 3, 21, 2] 2 and 21 This is the code of the lab before that wants me to add to it.

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Given the following function header: def longest_chain(lst: list[int]) -> int: Given a list of integers, return the length of the longest chain of 1's that start from the beginning. Precondition: 1st is non-empty which one of the cases below is the least useful to check? Select the best answer.