Answered: The function count_contains_og in…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

The function count_contains_og in python takes a list of strings and returns how many strings in the list contain 'og' / 'OG' / 'oG' / 'Og' (check for 'og', ignoring case).

Hint: Use the sequence membership operator in to help you check for 'og' in the individual strings. Create a lower-cased version of the string (lower), then use the in operator.

For example:

Test	Result
str_list = ['cat', 'dog', 'FROG', 'monkey'] print(count_contains_og(str_list))	2
strlist = ["X", "x"] print(count_contains_og(strlist))	0
list_of_one_og = ["Doggie"] print(count_contains_og(list_of_one_og))	1

Expert Solution

Step 1

Algorithm for the function count_contains_og(lst):

1. Initialize count to 0 to count the "og".

2. Calculate the length of lst as length = Length(lst).

3. Run loop from i=0 to i=length - 1:

3.1. Convert lst[i] into lower case.

3.2. IF "og" is in lst[i]:

count = count + 1

4. Return count.

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