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Given the following function: def nPrint (message, n): while n > 0: print (message, end='') n -= 1 What will be displayed by the call nPrint('a', 4)? Select one: О а. ааааа O b. aaaa О с. ааа O d. Nothing, nPrint('a', 4) is an invalid call to the function. O e. Nothing, def nPrint(message, n): is an invalid function definition.

Given the following function: def nPrint (message, n): while n > 0: print (message, end='') n -= 1 What will be displayed by the call nPrint('a', 4)? Select one: О а. ааааа O b. aaaa О с. ааа O d. Nothing, nPrint('a', 4) is an invalid call to the function. O e. Nothing, def nPrint(message, n): is an invalid function definition.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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### Understanding Function Behavior in Python Given the following function: ```python def nPrint(message, n): while n > 0: print(message, end='') n -= 1 ``` #### Question: What will be displayed by the call `nPrint('a', 4)`? #### Options: a. aaaaa b. aaaa c. aaa d. Nothing, `nPrint('a', 4)` is an invalid call to the function. e. Nothing, `def nPrint(message, n):` is an invalid function definition. ### Explanation: 1. **Function Definition**: - The function `nPrint` takes two parameters: `message` and `n`. - It enters a while loop that continues as long as `n` is greater than 0. - Inside the loop, it prints the `message` and subtracts 1 from `n`. 2. **Call Analysis**: - When `nPrint('a', 4)` is called: - Initially, `n` is 4. It prints 'a' and then decrements `n` to 3. - `n` is 3. It prints 'a' and then decrements `n` to 2. - `n` is 2. It prints 'a' and then decrements `n` to 1. - `n` is 1. It prints 'a' and then decrements `n` to 0. - Now `n` is 0, so the loop exits. Therefore, the result of calling `nPrint('a', 4)` is printing the character 'a' four times in a row, resulting in "aaaa". ### Correct Option: **b. aaaa**
Transcribed Image Text:### Understanding Function Behavior in Python Given the following function: ```python def nPrint(message, n): while n > 0: print(message, end='') n -= 1 ``` #### Question: What will be displayed by the call `nPrint('a', 4)`? #### Options: a. aaaaa b. aaaa c. aaa d. Nothing, `nPrint('a', 4)` is an invalid call to the function. e. Nothing, `def nPrint(message, n):` is an invalid function definition. ### Explanation: 1. **Function Definition**: - The function `nPrint` takes two parameters: `message` and `n`. - It enters a while loop that continues as long as `n` is greater than 0. - Inside the loop, it prints the `message` and subtracts 1 from `n`. 2. **Call Analysis**: - When `nPrint('a', 4)` is called: - Initially, `n` is 4. It prints 'a' and then decrements `n` to 3. - `n` is 3. It prints 'a' and then decrements `n` to 2. - `n` is 2. It prints 'a' and then decrements `n` to 1. - `n` is 1. It prints 'a' and then decrements `n` to 0. - Now `n` is 0, so the loop exits. Therefore, the result of calling `nPrint('a', 4)` is printing the character 'a' four times in a row, resulting in "aaaa". ### Correct Option: **b. aaaa**
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