Given the following equilibrium equation: CH4(g) + 2O2(g) <--> CO2(g) + 2H₂O(g) + heat What would be the effect of Removing O₂ from the reaction mixture. No effect and CO₂ concentration goes down. Shifts to the left and CO₂ concentration increases. Shifts to the right and H₂O concentration increase. Shifts to the left and CH4 concentration increases.
Given the following equilibrium equation: CH4(g) + 2O2(g) <--> CO2(g) + 2H₂O(g) + heat What would be the effect of Removing O₂ from the reaction mixture. No effect and CO₂ concentration goes down. Shifts to the left and CO₂ concentration increases. Shifts to the right and H₂O concentration increase. Shifts to the left and CH4 concentration increases.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding Chemical Equilibrium Shifts: A Case Study
**Given the following equilibrium equation:**
\[ \text{CH}_4(g) + 2\text{O}_2(g) \leftrightharpoons \text{CO}_2(g) + 2\text{H}_2\text{O}(g) + \text{heat} \]
**Question:**
What would be the effect of removing \(\text{O}_2\) from the reaction mixture?
### Options:
- \( \circ \) **No effect and \(\text{CO}_2\) concentration goes down.**
- \( \circ \) **Shifts to the left and \(\text{CO}_2\) concentration increases.**
- \( \circ \) **Shifts to the right and \(\text{H}_2\text{O}\) concentration increases.**
- \( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**
### Explanation:
In a chemical equilibrium, removing a reactant or a product will disturb the equilibrium, causing the system to shift in a direction that will counteract the change, according to **Le Chatelier's Principle**.
- **If \(\text{O}_2\) is removed**, the system will attempt to replace the \(\text{O}_2\) by shifting the equilibrium to the left, favoring the reactants.
Among the given options, the correct answer would be:
\( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**
This is because the reaction will shift towards the reactants to produce more \(\text{O}_2\), thereby increasing the concentration of \(\text{CH}_4\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2774ef-0163-4a47-a649-5765c1b29ef1%2F68b21852-2ccd-48d0-8754-7f2961d316cd%2Ftuiduhd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Chemical Equilibrium Shifts: A Case Study
**Given the following equilibrium equation:**
\[ \text{CH}_4(g) + 2\text{O}_2(g) \leftrightharpoons \text{CO}_2(g) + 2\text{H}_2\text{O}(g) + \text{heat} \]
**Question:**
What would be the effect of removing \(\text{O}_2\) from the reaction mixture?
### Options:
- \( \circ \) **No effect and \(\text{CO}_2\) concentration goes down.**
- \( \circ \) **Shifts to the left and \(\text{CO}_2\) concentration increases.**
- \( \circ \) **Shifts to the right and \(\text{H}_2\text{O}\) concentration increases.**
- \( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**
### Explanation:
In a chemical equilibrium, removing a reactant or a product will disturb the equilibrium, causing the system to shift in a direction that will counteract the change, according to **Le Chatelier's Principle**.
- **If \(\text{O}_2\) is removed**, the system will attempt to replace the \(\text{O}_2\) by shifting the equilibrium to the left, favoring the reactants.
Among the given options, the correct answer would be:
\( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**
This is because the reaction will shift towards the reactants to produce more \(\text{O}_2\), thereby increasing the concentration of \(\text{CH}_4\).
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