Given the following equilibrium equation: CH4(g) + 2O2(g) <--> CO2(g) + 2H₂O(g) + heat What would be the effect of Removing O₂ from the reaction mixture. No effect and CO₂ concentration goes down. Shifts to the left and CO₂ concentration increases. Shifts to the right and H₂O concentration increase. Shifts to the left and CH4 concentration increases.

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### Understanding Chemical Equilibrium Shifts: A Case Study

**Given the following equilibrium equation:**

\[ \text{CH}_4(g) + 2\text{O}_2(g) \leftrightharpoons \text{CO}_2(g) + 2\text{H}_2\text{O}(g) + \text{heat} \]

**Question:**
What would be the effect of removing \(\text{O}_2\) from the reaction mixture?

### Options:
- \( \circ \) **No effect and \(\text{CO}_2\) concentration goes down.**
  
- \( \circ \) **Shifts to the left and \(\text{CO}_2\) concentration increases.**
  
- \( \circ \) **Shifts to the right and \(\text{H}_2\text{O}\) concentration increases.**
  
- \( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**

### Explanation:

In a chemical equilibrium, removing a reactant or a product will disturb the equilibrium, causing the system to shift in a direction that will counteract the change, according to **Le Chatelier's Principle**.

- **If \(\text{O}_2\) is removed**, the system will attempt to replace the \(\text{O}_2\) by shifting the equilibrium to the left, favoring the reactants.

Among the given options, the correct answer would be:

\( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.**

This is because the reaction will shift towards the reactants to produce more \(\text{O}_2\), thereby increasing the concentration of \(\text{CH}_4\).
Transcribed Image Text:### Understanding Chemical Equilibrium Shifts: A Case Study **Given the following equilibrium equation:** \[ \text{CH}_4(g) + 2\text{O}_2(g) \leftrightharpoons \text{CO}_2(g) + 2\text{H}_2\text{O}(g) + \text{heat} \] **Question:** What would be the effect of removing \(\text{O}_2\) from the reaction mixture? ### Options: - \( \circ \) **No effect and \(\text{CO}_2\) concentration goes down.** - \( \circ \) **Shifts to the left and \(\text{CO}_2\) concentration increases.** - \( \circ \) **Shifts to the right and \(\text{H}_2\text{O}\) concentration increases.** - \( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.** ### Explanation: In a chemical equilibrium, removing a reactant or a product will disturb the equilibrium, causing the system to shift in a direction that will counteract the change, according to **Le Chatelier's Principle**. - **If \(\text{O}_2\) is removed**, the system will attempt to replace the \(\text{O}_2\) by shifting the equilibrium to the left, favoring the reactants. Among the given options, the correct answer would be: \( \circ \) **Shifts to the left and \(\text{CH}_4\) concentration increases.** This is because the reaction will shift towards the reactants to produce more \(\text{O}_2\), thereby increasing the concentration of \(\text{CH}_4\).
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