Given the following equilibrium constants at 433°C,1Na20(s) = 2 Na(1) +02 (9) K1 = 5 x 10-2521NaO(g) - Na(1)+;02(9)K28 x 10-5-29Na2 O2 (s) = 2 Na(1) + O2 (9)NaO2 (s) = Na(1) + O2 (9)K3= 4 × 10-14KĄ3 x 10determine the values for the equilibrium constants for the following reactions:a. Na20(s) +1O2 (g) = Na2 O2 (8)Equilibrium constant =b. NaO(g) + Na, 0(s) = Na2O2(s) + Na(1)Equilibrium constantc. 2 NaO(g) = Na2 O2 (s)Equilibrium constant =(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

To Solve this problem we will use the given equilibrium equations to get the equilibrium constant .

Given the following equilibrium constants at 433°C, 1 Na2 0(s) = 2 Na(l) + 02 (g) Kị = 5 × 10¬25 2 O2 (9) Na2 02 (s) = 2 Na(1) + O2 (9) NaO2 (s) = Na(l) + O2 (g) NaO(g) = Na(1) + K2 = 8 x 10- -29 K3 = 4 x 10 K4 = 3 x 10-14 determine the values for the equilibrium constants for the following reactions: 1 a. Naz0(8) +02 (g) = Na2O2(s) Equilibrium constant = b. NaO(g) + Na20(s) = Na2O2(s) + Na(1) Equilibrium constant = c. 2 NaO(g) = Na2O2(s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Given the following equilibrium constants at 433°C, 1 Na2 0(s) = 2 Na(l) + 02 (g) Kị = 5 × 10¬25 2 O2 (9) Na2 02 (s) = 2 Na(1) + O2 (9) NaO2 (s) = Na(l) + O2 (g) NaO(g) = Na(1) + K2 = 8 x 10- -29 K3 = 4 x 10 K4 = 3 x 10-14 determine the values for the equilibrium constants for the following reactions: 1 a. Naz0(8) +02 (g) = Na2O2(s) Equilibrium constant = b. NaO(g) + Na20(s) = Na2O2(s) + Na(1) Equilibrium constant = c. 2 NaO(g) = Na2O2(s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Given the following equilibrium constants at 433°C,
1
Na20(s) = 2 Na(1) +02 (9) K1 = 5 x 10-25
2
1
NaO(g) - Na(1)+;02(9)
K2
8 x 10-5
-29
Na2 O2 (s) = 2 Na(1) + O2 (9)
NaO2 (s) = Na(1) + O2 (9)
K3
= 4 × 10
-14
KĄ
3 x 10
determine the values for the equilibrium constants for the following reactions:
a. Na20(s) +
1
O2 (g) = Na2 O2 (8)
Equilibrium constant =
b. NaO(g) + Na, 0(s) = Na2O2(s) + Na(1)
Equilibrium constant
c. 2 NaO(g) = Na2 O2 (s)
Equilibrium constant =
(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

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