Given the following equilibria: AgBr(s) ⇌ Ag+(aq) + Br–(aq); Ksp= 5.0 x 10–13 Ag+(aq) + S2O32–(aq) ⇌ Ag(S2O3)–(aq); K1= 7.4 x 108 Ag(S2O3)–(aq) + S2O32–(aq) ⇌ Ag(S2O3)23–(aq); K2= 3.9 x 104 (a) What is the equilibrium constant Kf for the formation of complex ion, Ag(S2O3)23–? Ag+(aq) + 2S2O32–(aq) ⇌ Ag(S2O3)23–(aq); Kf= ?

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Given the following equilibria:

AgBr(s) ⇌ Ag+(aq) + Br(aq); Ksp= 5.0 x 10–13

Ag+(aq) + S2O32–(aq) ⇌ Ag(S2O3)(aq); K1= 7.4 x 108

Ag(S2O3)(aq) + S2O32–(aq) ⇌ Ag(S2O3)23–(aq); K2= 3.9 x 104

(a) What is the equilibrium constant Kf for the formation of complex ion, Ag(S2O3)23–?

Ag+(aq) + 2S2O32–(aq) ⇌ Ag(S2O3)23–(aq); Kf= ?

(b) What is the equilibrium constant Kc for thefollowing reaction:

AgBr(s) + 2S2O32–(aq) ⇌ Ag(S2O3)23–(aq) + Br(aq); Kc= ?

(c) Calculate the solubility of AgBr (in mol/L) in 0.50 M Na2S2O3solution.

(d) How many grams of AgBr will dissolve in 475mL of 0.50 M Na2S2O3?

Expert Solution
Step 1

AgBr(s) <-------> Ag+(aq) + Br-(aq)

Ksp = 5*10-13

Ag+(aq) + S2O32–(aq) ⇌ Ag(S2O3)(aq); K1= 7.4 x 108

Ag(S2O3)(aq) + S2O32–(aq) ⇌ Ag(S2O3)23–(aq); K2= 3.9 x 104

 

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