Given the following data for: Mass of test tube, beaker, cyclohexane =100.17 g Mass of test tube and beaker = 84.07 g Freezing point of cyclohexane = 6.59 °C Mass of weighing paper + naphthalene = 1.080 g Mass of weighing paper = 0.928 g Freezing point solution = 5.11 °C Kf = 20.8 °C/m Determine the following: a. mass of cyclohexane in g (2 decimal places) b. mass of naphthalene in g ( 4 decimal place) c. freezing point depression (2 decimal place)
Given the following data for:
Mass of test tube, beaker, cyclohexane =100.17 g
Mass of test tube and beaker = 84.07 g
Freezing point of cyclohexane = 6.59 °C
Mass of weighing paper + naphthalene = 1.080 g
Mass of weighing paper = 0.928 g
Freezing point solution = 5.11 °C
Kf = 20.8 °C/m
Determine the following:
a. mass of cyclohexane in g (2 decimal places)
b. mass of naphthalene in g ( 4 decimal place)
c. freezing point depression (2 decimal place)
d. molality of solution (3 significant figures)
e. moles of naphthalene ( 3 significant figures)
f. molar mass of naphthalene experimentally (3 significant figures)
g. % error if theoretical molar mass of naphthalene is 128.17 g/mole, USE ABSOLUTE VALUE. (3 significant figure)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images