Given the following data for a reaction between A and B:Initial Rate (M/S)Initial Conc. of [A]Initial Conc. of [B]0.681.722.445.443.442.442.8 x 10 21.720.10What is the rate law for this reaction?Rate = k[A][B]³Rate = k[A][B]4Rate = k[A]*[B]%3DRate = k[A]°[B]%3DO Rate =K[A]?[B]?A Moving to another question will save this response.

From the given data rate law of the reaction is, Rate = k[A]m[B]n . Here m and n are the order of…

Answered: Given the following data for a reaction…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Given the following data for a reaction between A and B:
Initial Rate (M/S)
Initial Conc. of [A]
Initial Conc. of [B]
0.68
1.72
2.44
5.44
3.44
2.44
2.8 x 10 2
1.72
0.10
What is the rate law for this reaction?
Rate = k[A][B]³
Rate = k[A][B]4
Rate = k[A]*[B]
%3D
Rate = k[A]°[B]
%3D
O Rate =
K[A]?[B]?
A Moving to another question will save this response.

Expert Solution

Step 1

From the given data rate law of the reaction is, Rate = k[A]^m[B]ⁿ. Here m and n are the order of reaction with respect to reactant A and B respectively.

To get the rate law we need to find the values of exponents m and n .

Step 2

By using numbers the values of initial Rate₁,Rate₂, Rate₃with the respective concentrations of reactants are given

The equation for Rate₁will be,0.68=k [1.72]^m[2.44]ⁿ

The equation for Rate₂will be, 5.44 = k[3.44]^m[2.44]ⁿ

By dividing the equation for Rate₂by Rate₁,

$\begin{array}{rcl} \frac{5.44}{0.68} & = & \frac{k {[3.44]}^{m} {[2.44]}^{n}}{k {[1.72]}^{m} {[2.44]}^{n}} \\ 8 & = & {(2)}^{m} \\ m & = & 3 \end{array}$

Thus, the order of reaction with respect to A is 3.

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