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Given the following data, 1/2 H2(g) + 1/2 Cl₂(g) – HCI(g) H2(g) + 1/2O2(g) → H₂O(l) ΔγH° = −92.3 kJ.mol-1 ArH=-285.8 kJ.mol-1 calculate the value of ArH for the reaction described below. (Answer in 4 sig fig) 2 Cl₂(g) + 2 H₂O(1)→ 4 HCl(g) + O2(g)

Given the following data, 1/2 H2(g) + 1/2 Cl₂(g) – HCI(g) H2(g) + 1/2O2(g) → H₂O(l) ΔγH° = −92.3 kJ.mol-1 ArH=-285.8 kJ.mol-1 calculate the value of ArH for the reaction described below. (Answer in 4 sig fig) 2 Cl₂(g) + 2 H₂O(1)→ 4 HCl(g) + O2(g)

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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Given the following data, 1/2 H2(g) + 1/2 Cl₂(g) → HCI(g) H2(g) + 1/2O2(g) – H₂O(l) ArHᵒ = -92.3 kJ.mol-1 ΔγH° = -285.8 kJ.mol-1 calculate the value of ArH for the reaction described below. (Answer in 4 sig fig) 2 Cl₂(g) + 2 H₂O(1) → 4 HCl(g) + O₂(g)
Transcribed Image Text:Given the following data, 1/2 H2(g) + 1/2 Cl₂(g) → HCI(g) H2(g) + 1/2O2(g) – H₂O(l) ArHᵒ = -92.3 kJ.mol-1 ΔγH° = -285.8 kJ.mol-1 calculate the value of ArH for the reaction described below. (Answer in 4 sig fig) 2 Cl₂(g) + 2 H₂O(1) → 4 HCl(g) + O₂(g)
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