Given the following combustion reactions, which will have the most negative molar entropy change? Select one: O a. CoH20() + 1402(g) → 9CO29) + 10H209 O b. C;H16() + 1102(g) → 7CO2(g) + 8H20 Oc. 2C3H180) + 2502(g) → 16C02(g) + 18H20M O d. 2C6H140) + 1902(9) → 12002(9) + 14H20M

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Given the following combustion reactions, which will have the most negative molar entropy change?
Select one:
O a. CoH20() + 1402(g) → 9CO29) + 10H209
O b. C;H16() + 1102(g) → 7CO2(g) + 8H20
O c. 2C3H180) + 2502(9) → 16C02(g) + 18H20M
O d. 2C6H140) + 1902(g) → 12002(9) + 14H20M
The chemical formula of the antiviral drug against COVID-19 molnupiravir is C13H19N307. How many oxygen
atoms are present in 800.0 mg of molnupiravir?
Relative atomic masses:
H= 1.008; C = 12.011; N= 14.007; 0 = 15.999
Select one:
O a. 1.024 x 102² o atoms
O b. 1.463 x 1021 o atoms
O c. 1.902 x 1022 o atoms
O d. 7.315 x 1021 o atoms
A 250.0-ml sample of 0.125 M NagPO, is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Caą(PO4)2. The net
ionic equation for the reaction is given below:
3 Са
"fag) + 2 PO, (a) → Ca3(PO4)2(=)
What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are
additive?
Select one:
O a. 4.17x 10 MPO,3-
O b. 2.5 x 10-2 M Ca2+
О с. 9.38 х 10-3М Са2*
O d. 5.83 x 10-2 M PO,3-
Transcribed Image Text:Given the following combustion reactions, which will have the most negative molar entropy change? Select one: O a. CoH20() + 1402(g) → 9CO29) + 10H209 O b. C;H16() + 1102(g) → 7CO2(g) + 8H20 O c. 2C3H180) + 2502(9) → 16C02(g) + 18H20M O d. 2C6H140) + 1902(g) → 12002(9) + 14H20M The chemical formula of the antiviral drug against COVID-19 molnupiravir is C13H19N307. How many oxygen atoms are present in 800.0 mg of molnupiravir? Relative atomic masses: H= 1.008; C = 12.011; N= 14.007; 0 = 15.999 Select one: O a. 1.024 x 102² o atoms O b. 1.463 x 1021 o atoms O c. 1.902 x 1022 o atoms O d. 7.315 x 1021 o atoms A 250.0-ml sample of 0.125 M NagPO, is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Caą(PO4)2. The net ionic equation for the reaction is given below: 3 Са "fag) + 2 PO, (a) → Ca3(PO4)2(=) What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive? Select one: O a. 4.17x 10 MPO,3- O b. 2.5 x 10-2 M Ca2+ О с. 9.38 х 10-3М Са2* O d. 5.83 x 10-2 M PO,3-
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