2. Given the equations from Joint B Solve for the force in BD and BE.600 lb600 lb600 lb600 lbBDD300 lbB.F2 ft 4 in.300 lb|6 ft1500 lbВЕEGH.8 ft 8 ft→-8 ft→-8 ft8.BD8.ΣΕ-0= 1500|8.BE10106.= 0 =1500101,600 – BD86.+ BE103. Solve for x and y.1200 lb30°

Answered: Given the equations from Joint B Solve…

Given the equations from Joint B Solve for the force in BD and BE. 600 lb 600 lb 600 lb 600 lb BD D 300 lb B. 2 ft 4 in. 300 lb 6 ft 1500 lb ВЕ C E| G| H. 8 ft 8 ft 8 ft -8 ft-

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

2. Given the equations from Joint B Solve for the force in BD and BE.
600 lb
600 lb
600 lb
600 lb
BD
D
300 lb
B.
F
2 ft 4 in.
300 lb|
6 ft
1500 lb
ВЕ
E
G
H.
8 ft 8 ft→-8 ft→-8 ft
8.
BD
8.
ΣΕ-0= 1500|
8.
BE
10
10
6.
= 0 =1500
10
1,
600 – BD
8
6.
+ BE
10
3. Solve for x and y.
1200 lb
30°

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