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Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20 inductor is 10 j2 N + j3 N I 12 Ωξ V 39 I, -j16 N; V, = = 150 /0° V V1 = (78 – j104) V V2 = (72 + j104) V I = (-26 – j52) A I, = (-2 + j6) A V3 = (150 – j130) V I = (-24 – j58) A +

Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20 inductor is 10 j2 N + j3 N I 12 Ωξ V 39 I, -j16 N; V, = = 150 /0° V V1 = (78 – j104) V V2 = (72 + j104) V I = (-26 – j52) A I, = (-2 + j6) A V3 = (150 – j130) V I = (-24 – j58) A +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20 inductor is - 10 j2 N + j3 N 1Ω 12 Ωξ V. 39 I, -j16 07 V, = 150 /0° V V1 = (78 – j104) V V2 = (72 + j104) V I = (-26 – j52) A I, = (-2 + j6) A I2 = (-24 – j58) A V3 = (150 – j130) V
Transcribed Image Text:Given the circuit below and the associated set of voltages and currents, the reactive Power developed by j20 inductor is - 10 j2 N + j3 N 1Ω 12 Ωξ V. 39 I, -j16 07 V, = 150 /0° V V1 = (78 – j104) V V2 = (72 + j104) V I = (-26 – j52) A I, = (-2 + j6) A I2 = (-24 – j58) A V3 = (150 – j130) V
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