Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
Q1e) Find the equivalent inductance, Leq, at terminals a-b of the circuit given. Show all work. do 25 mH 10 mH Lea 60 mH 20 mH 30 mH b

Q1e) Find the equivalent inductance, Leq, at terminals a-b of the circuit given. Show all work. do 25 mH 10 mH Lea 60 mH 20 mH 30 mH b

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
**Question 1(c): Equivalent Inductance Calculation** **Problem Statement:** Find the equivalent inductance, \( L_{eq} \), at terminals \( a-b \) of the circuit given. Show all work. **Circuit Diagram:** The provided circuit diagram contains the following components: - An inductor of 10 mH connected in series. - An inductor of 60 mH, 25 mH, 20 mH, and 30 mH connected in a combination of series and parallel. Here is the circuit layout in detail: - Inductor 10 mH connected in series with a parallel combination - The left branch of the parallel combination has an inductor of 25 mH. - The right branch parallel to the 25 mH inductor consists of a series combination of 60 mH, 20 mH, and 30 mH inductors. **Equivalent Inductance Calculation:** 1. **Identify Series and Parallel Combinations:** - In the right branch: - Inductors 60 mH, 20 mH, and 30 mH are in series. - The equivalent inductance of series inductors ( \( L_s \) ): \( L_s = 60 + 20 + 30 = 110 \) mH 2. **Combine Parallel Inductors:** - The inductors in the left and right branches are in parallel. - Inductors in parallel combine as: \[ \frac{1}{L_p} = \frac{1}{L_1} + \frac{1}{L_2} \] Where \( L_1 \) is 25 mH, and \( L_2 \) is 110 mH. \[ \frac{1}{L_p} = \frac{1}{25} + \frac{1}{110} = 0.04 + 0.0091 \approx 0.0491 \ (\text{in } \text{mH}^{-1}) \] Therefore: \[ L_p \approx \frac{1}{0.0491} \approx 20.37 \ \text{mH} \] 3. **Add the Series Inductance:** - Finally, add the 10 mH series inductor to the parallel combination:
Transcribed Image Text:**Question 1(c): Equivalent Inductance Calculation** **Problem Statement:** Find the equivalent inductance, \( L_{eq} \), at terminals \( a-b \) of the circuit given. Show all work. **Circuit Diagram:** The provided circuit diagram contains the following components: - An inductor of 10 mH connected in series. - An inductor of 60 mH, 25 mH, 20 mH, and 30 mH connected in a combination of series and parallel. Here is the circuit layout in detail: - Inductor 10 mH connected in series with a parallel combination - The left branch of the parallel combination has an inductor of 25 mH. - The right branch parallel to the 25 mH inductor consists of a series combination of 60 mH, 20 mH, and 30 mH inductors. **Equivalent Inductance Calculation:** 1. **Identify Series and Parallel Combinations:** - In the right branch: - Inductors 60 mH, 20 mH, and 30 mH are in series. - The equivalent inductance of series inductors ( \( L_s \) ): \( L_s = 60 + 20 + 30 = 110 \) mH 2. **Combine Parallel Inductors:** - The inductors in the left and right branches are in parallel. - Inductors in parallel combine as: \[ \frac{1}{L_p} = \frac{1}{L_1} + \frac{1}{L_2} \] Where \( L_1 \) is 25 mH, and \( L_2 \) is 110 mH. \[ \frac{1}{L_p} = \frac{1}{25} + \frac{1}{110} = 0.04 + 0.0091 \approx 0.0491 \ (\text{in } \text{mH}^{-1}) \] Therefore: \[ L_p \approx \frac{1}{0.0491} \approx 20.37 \ \text{mH} \] 3. **Add the Series Inductance:** - Finally, add the 10 mH series inductor to the parallel combination:
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Inductor
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS