Given that z is a standard normalrandom variable, computeP(z > -2.14).Select one:O a.0.0166Ob.0.01540.0162O d.0.9838e.0.9834Of.0.9842O g. 0.0158O h.0.9846

Answered: Image /qna-images/answer/7c188924-1d21-4ede-8201-34487fcb79b5.jpg

Answered: Given that z is a standard normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Let x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional player. A random sample of n = 6 professional baseball players gave the following information. 0.348 0.274 0.340 0.248 0.367 0.269 y 2.8 7.6 4.0 8.6 3.1 11.1 Σχ= 1.846, Ey = 37.2, Ex² = 0.580334, Ey² = 288.38, Exy = 10.6732, and r = -0.913. %3D (b) Use a 10% level of significance to test the claim that p + 0. (Use 2 decimal places.) t critical t + (d) Find the predicted percentage ŷ of strikeouts for a player with an x = 0.346 batting average. (Use 2 decimal places.) % (e) Find a 95% confidence interval for y when x = 0.346. (Use 2 decimal places.) lower limit % upper limit % (f) Use a 10% level of significance to test the claim that ß + 0. (Use 2 decimal places.) t critical t + (g) Find a 95% confidence interval for B and interpret its meaning. (Use 2 decimal places.) lower limit upper limit
Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be a random variable that represents the percentage of successful field goals a professional basketball player makes in a season. A random sample of n = 6 professional basketball players gave the following information. x 69 66 63 65 76 76 y 54 53 51 43 47 45 Verify that Se ≈ 4.739, a ≈ 67.050, b ≈ –0.263, and , ∑x =415, ∑y =293, ∑x2 =28,863, and ∑y2 =14,409, and find a 90% confidence interval for β and interpret its meaning. Round your final answers to three decimal places. answer choices: The 90% confidence interval for β is from –0.993 to 0.466 and means that for every percentage increase in successful free throws, there is 90% confidence that the percentage of successful field goals increases by an amount between –0.99 and 0.47. The 90% confidence interval for β is from –1.065 to 0.539 and means that for every percentage…
Let X be a discrete random variable with the following PMF PX(x) = 0.10 for x = 0.20 = 0.20 for x = 0.40 = 0.20 for x = 0.50 = 0.30 for x = 0.80 = 0.20 for x = 1.00 = 0.00 otherwise a. Find Rx, the range of the random variable X. b. Find P (X≤0.50). c. Find P (0.25 < X < 0.75). d. Find P (X = 0.20 | X<.060).
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Let x be a normally distributed random variable with the following parameters: μ = 135.628 σ = 28.622 12 What is the probability that x will be below 100 ? a 0.1343 b 0.1243 c 0.1151 d 0.1066
Let x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information. x 0.318 0.272 0.340 0.248 0.367 0.269 y 3.4 8.0 4.0 8.6 3.1 11.1 Σx = 1.814, Σy = 38.2, Σx2 = 0.559262, Σy2 = 298.34, Σxy = 10.8736, and r ≈ -0.874. (d) Find the predicted percentage of strikeouts for a player with an x = 0.35 batting average. (Use 2 decimal places.)%(e) Find a 95% confidence interval for y when x = 0.35. (Use 2 decimal places.) lower limit % upper limit % (f) Use a 1% level of significance to test the claim that β ≠ 0. (Use 2 decimal places.) t critical t ±
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Let x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information. x 0.318 0.272 0.340 0.248 0.367 0.269 y 3.4 8.0 4.0 8.6 3.1 11.1 Σx = 1.814, Σy = 38.2, Σx2 = 0.559262, Σy2 = 298.34, Σxy = 10.8736, and r ≈ -0.874. (e) Find a 95% confidence interval for y when x = 0.35. (Use 2 decimal places.) lower limit % upper limit (g) Find a 95% confidence interval for β and interpret its meaning. (Use 2 decimal places.) lower limit upper limit
If z is a standard normal random variable, then P (1.83 < z < 2.38) is:
Let x be a random variable that represents the percentage of successful free throws a professional basketball player makes in a season. Let y be a random variable that represents the percentage of successful field goals a professional basketball player makes in a season. A random sample of n = 6 professional basketball players gave the following information. x 73 74 80 66 77 77 y 50 52 45 46 52 53 Verify that Se ≈ 3.694, a ≈ 38.254, b ≈ 0.153, and , ∑x =447, ∑y =298, ∑x2 =33,419, and ∑y2 =14,858, and use a 5% level of significance to find the P-value for the test that claims that β is greater than zero. Group of answer choices Since the P-value is greater than α = 0.05, we reject the null hypothesis that the population slope β is equal to zero in favor of the alternate hypothesis that the population slope β is greater than zero. Since the P-value is equal to α = 0.05, we fail to reject the null hypothesis that the population slope β is equal to zero in favor of the…

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Given that z is a standard normal random variable, compute P(z > -2.14). Select one: O a. 0.0166 O b. 0.0154 O C. 0.0162 d. 0.9838 O e. 0.9834 O f. 0.9842 O g. 0.0158 O h. 0.9846