14/17 Given that pKa for phenol is 9.95 and pKa for the ammonium ion is 9.24, will the following reaction befavorable? (Will the products be favored at equilibrium?)HO+ NH3phenoxide ionphenolpKa = 9.95ammoniaammonium ionpKa = 9.24 Draw the most stable conformer of trans-1-t-butyl-3-methylcyclohexane. Your structure shouldclearly distinguish between all axial and equatorial positions.

Since, you have asked multiple questions then we will solved first question for you by details…

Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) + NH2 phenol pK, = 9.95 ammonia phenoxide ion ammonium ion pKa = 9.24

Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) + NH2 phenol pK, = 9.95 ammonia phenoxide ion ammonium ion pKa = 9.24

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

14/17

Given that pKa for phenol is 9.95 and pKa for the ammonium ion is 9.24, will the following reaction be
favorable? (Will the products be favored at equilibrium?)
HO
+ NH3
phenoxide ion
phenol
pKa = 9.95
ammonia
ammonium ion
pKa = 9.24

Draw the most stable conformer of trans-1-t-butyl-3-methylcyclohexane. Your structure should
clearly distinguish between all axial and equatorial positions.

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