Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) + NH2 phenol pK, = 9.95 ammonia phenoxide ion ammonium ion pKa = 9.24
Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) + NH2 phenol pK, = 9.95 ammonia phenoxide ion ammonium ion pKa = 9.24
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Given that pKa for phenol is 9.95 and pKa for the ammonium ion is 9.24, will the following reaction be
favorable? (Will the products be favored at equilibrium?)
HO
+ NH3
phenoxide ion
phenol
pKa = 9.95
ammonia
ammonium ion
pKa = 9.24

Transcribed Image Text:Draw the most stable conformer of trans-1-t-butyl-3-methylcyclohexane. Your structure should
clearly distinguish between all axial and equatorial positions.
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